fred, on Jan 4 2005, 08:42 PM, said:
Your next assignment:
KQ10987
32
You can afford to lose only 1 trick.
Well Fred, here's my 2 cents:
First, it doesn't matter what you do in the following cases, 5-0 break, AJx or AJxx offside, singleton A either side. If the J is singleton onside then you know what to do.
Now, low to the 10 right away loses anytime the J is offside but it's not as silly as you may think since most of those cases are already covered above. So, the only relevant ones that fail are AJ, J(x)(x) - 4 cases. Still seems like a bad idea, just not as dumb as it first appears. Note the following: if LHO AJxx you must lead low to the 10 and then low to the 9 but that's only 1 case so we'll assume the first lead is to the king.
If the first lead loses to the A on the right, all other holdings having been eliminated above, the opps holdings will be Jx opposite x or xx opposite J so you must guess. Likewise, you have no problem if LHO goes up A. If the K is allowed to win here's what ya got in the opps hands: Jx - A, Ax - J, AJ - x. Obviously the last holding is trivial since you will know what to do once LHO plays. So it really comes down to a guess: which one has the J and which one has the A? So, another 50-50 shot. I hope I have this right.
Incidentally, it took me a long time to work this out. Really interesting problem, Fred, thanks.
This post has been edited by Rebound: 2005-January-05, 17:02
I'd rather have a bottle in front of me than a frontal lobotomy - but it might improve my bridge.