The first play already gives us a clue. E probably doesn't have the Q. Draw trumps in two rounds, E started with two spades and also had the J.
Now play three rounds of diamonds, ending in hand, since there's no reason not to. We might learn something about the diamond distribution, and might get to see a discard.
Diamonds are 4-3, so E has at most two clubs. Now we have to play clubs. We want to lose the club trick to E - if we're lucky, he'll fear a ruff and sluff (we all learned it's bad) and might return a club, since he has no way of knowing I don't hold the fourth diamond.
So at trick 7, play the club 7, to make it more difficult for the defense to count (if I play the 3 to the 4 and E wins something high, W can be pretty sure I have all the middle ones). If W will play K or Q, we play the ace, return to hand and play another club towards the J. E can't have three club, so this will bring the contract home.
W produces the 2. This is interesting. We all play second hand low, but if she had KQ she might be tempted to split (even though on this layout it loses), and by being able to produce the only "low" club (notice the sequence of spots between my hand an dummy) reduces the chance she only has two. So we duck. If clubs are 2-2 nothing bad happened yet. If they're 4-0, we just got on the road to winning the hand. If they're 3-1, then if the singleton is the remaining K or Q it's good for us and if it's the T we lose since W will score one of her K or Q of clubs. E wins the club king. This means he doesn't have the T, most likely. Now we wait for his return.
Trick 8. He thinks for a while and returns a heart. What is he thinking about? Assuming he's not thinking about what heart to return (he doesn't have the Q so he can't think it matters, really), he couldn't be thinking about returning his club Q if he has since he sees AJ in dummy. Could it be that he has the last diamond?
In any case, discard a club on his heart, W produces another heart, and ruff (high) in dummy.
Trick 9. Now return to hand with a trump. We know we're going to play a club towards dummy at some point, but the opponents might not have paid attention. They should know we have no hearts left, and if we have the fourth diamond it doesn't matter since it's high so my contract is made. They also know that unless I'm crazy, I have all the remaining trumps in my hand. Theoretically, they should know exactly what I hold -- but we still lose nothing by trying to see if they're still awake. Now we'll play trumps from hand before playing the other club, just to see what happens. It's unlikely we'll get a club pitch, of course, but let's see if both of them discard hearts confidently all the time. On the trump return to hand, both discard hearts. That's 8 out, E still has at least three of the remaining five. No surprises yet.
Trick 10. Let's play another trump and discard a low club from dummy. Now W thinks a bit and discards a heart. I discard a club, and E thinks and finally produces the last diamond. So that's what he's been thinking about after winning his ♣, and it also gives a complete count of his hand. He can't have any more clubs left, unless he felt like bidding 2♥ on a five-card suit with a single honor. We gave him a chance to err and he took it, hurray for us.
Let's say he doesn't make this mistake, and instead discards a heart. If we play another trump, we might learn something interesting, but we risk going two down instead of one down if we misguess the clubs.
In our theoretical trick 11, there are still ♣QT, a diamond and three hearts out there between the defenders' hands, with E having at least two of those three hearts, and either the last diamond, or the Q of clubs as his third card (we ruled out the T before). You will notice he can't just three hearts left - the defenders made another mistake in their discards, W didn't discard her Q of hearts, so I know the remaining hearts are 2-1. We play the club, W produces the club T we knew she had, and we play the J. If E had KQ tight all along and played the K, good for the opponents. But finessing now should have been our plan from trick 7. We know based on the bidding and the first six tricks that E doesn't have 3 or 4 clubs, so clubs are 2-2, 3-1 or 4-0. If they're 2-2, covering what W plays twice wins against anything that's not KQ tight with E, which is only one possible holding out of the six he could have. If they're 3-1, only the singleton T in E (1/4) defeats us. Everything we've learned so far still keeps us within those odds. After trick 7, it's given that clubs are 3-1 or 2-2, and the odds for 3-1 are much higher, both mathematically and based on the bidding. W only raised to 3 ♥, so she might not know they have an 11-card fit.