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How are the imps calculated?

#1 User is offline   brillage 

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Posted 2010-October-18, 09:32

I need a formula.

e.g.
16 tables in a pair tournment

thanks
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#2 User is offline   georgi 

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Posted 2010-October-18, 09:50

http://en.wikipedia....dge#IMP_scoring

#3 User is offline   brillage 

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Posted 2010-October-18, 10:30

georgi, on Oct 18 2010, 10:50 AM, said:


thank you
but not my anwer :rolleyes:
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#4 User is offline   bid_em_up 

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Posted 2010-October-18, 11:00

brillage, on Oct 18 2010, 12:30 PM, said:

georgi, on Oct 18 2010, 10:50 AM, said:


thank you
but not my anwer :rolleyes:

Huh? Then what are you looking for?
Is the word "pass" not in your vocabulary?
So many experts, not enough X cards.
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#5 User is offline   georgi 

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Posted 2010-October-18, 11:08

there is an example, just is not automated.

i think you need software, not formula. the formula is being given.

Quote

Example of averaged cross-imp scoring: Assume that you are one of five pairs who play Board 2 as N/S (you are vulnerable). On this board you bid and make 4 Spades, scoring +620, while the other four N/S pairs score -100, -100, -300, and +650. To figure out your averaged cross-imp score, you would create a table like the Cross-IMP example table below: after writing in the scores of you and your opponents in the bolded areas, you would then fill in the Score Delta row by subtracting each of the opponent's scores from yours. Then, you would fill in the IMPS Gained row by converting each of the score deltas into IMPS via the standard IMP table (e.g. 720 equates to 12 IMPs, because it falls in the range of 600 to 740 in the IMP table). You then add up those numbers and get 37 IMPS. To turn the 37 IMPS into a averaged  cross-IMP score, you simply divide that number by the number of competitors (37 IMPs divided by 4 competitors) to arrive at 9.25 as your averaged cross-IMP score



Other example :

NS pair 1: 430
NS pair 2: 400
NS pair 3: 150
NS pair 4: -50

To calculate the IMPs for the NS pair 1, using the averaged cross-imp way:
- Subtracting each three opponents’ scores from the NS pair 1’s score we have:
430 – 400 = 30
430 – 150 =280
430- (-50) = 480

- Convert the subtractions in IMPs:
30 = 1 IMP
280 = 7 IMPs
480 = 10 IMPs

Sum the IMPs up and divide them by 3 opponents and the result for the NS pair 1 is:
(1+7+10)/3 = 6 IMPs

The EW pair 1, who played this board on the same table with NS pair 1, will receive -6 IMPs accordingly.

Using the same steps the IMP scoring is done for all of the other pairs, NS pair 2, NS pair 3 and NS pair 4



You may continue it with putting 16 scores and do the rest for each NS / EW pairs

#6 User is offline   brillage 

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Posted 2010-October-18, 21:07

thanks georgi
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