jdonn, on Dec 23 2009, 01:34 PM, said:
kenrexford, on Dec 22 2009, 10:44 PM, said:
jdonn, on Dec 22 2009, 06:42 PM, said:
I also see no harm in playing 5NT with 11 certain tricks, no more and no less. Somehow I never seem to be able to tell that is the case during the bidding though.
So dense you are, worthy of two responses!
Whereas knowing that 11 tricks are available for our side might be an elusive task, knowing that the opponents have two defensive tricks seems rather easy, when the two tricks are Aces. When I have a choice between a 6-level contract and a 5-level contract, I am less concerned with "getting to 11" as I am about the opponents "getting to two."
Thank you for the insult, I'll learn to play bridge at your high level one day. I suppose when someone shows a 6 card suit in response to 1NT then tries for slam and then you find out you are off 2 aces, you are guaranteed to have the other 32 high card points and thus have complete certainty the opponents won't get a third trick. In that case you are doing very well to get to 5NT.
OMG!!!
I don't understand for the life of me why this is still an unclear issue.
Here's what happens. One person shows slam interest with length in a minor, and presumably no voids. If he has a void, he can see that aspect of his hand. It is in front of him.
So, he bids 4NT to show that hand -- slam interest. But, 4NT is passable.
Whether all of this so far makes any sense or not is irrelevant, because this is what we were presented with.
Then, Opener can decide to pass, declining, or to accept. Some proposed that acceptance means answering aces. Fine. Maybe this makes sense.
However, the objection was that a 5
♥ or 5
♠ answer leaves no solution if we have two clear losers. I said that this makes no sense, because 5NT is an option.
The question, then, is not whether we play in 5NT or 4NT, or even 5
♦. The question is whether on route to 6
♦ we might opt out at 5NT when we KNOW that there are two losers out there.
I don't give a crap whether we can get to 11 tricks or not in that situation. We know that we cannot get to 12 before the opponents get to 2, so 5NT is the only POSSIBLE contract. 5NT will not be a certainty. 32 HCP are not known to exist. The defense could set 5NT. But, 5NT has in theory a chance. 6
♦ does not.
Therefore, to my simple thinking, if I have a choice between a 6
♦ contract, where I know that the opponents can cash at least two tricks, and a 5NT contract, where I know that the opponents can cash at least two tricks, I hope that 2 is all that they can cash and bid 5NT. If I am right, I make 5NT. If I am wrong, 5NT goes down just like 6
♦, and I am no worse off. I might even be better off, down only one instead of down two. That would be nice too.
Unfortunately, there is no bid that takes back. I cannot bid, for example, 5
♦ over 5
♥. I also cannot answer Aces with two bids, using normal methods. If 5
♣ was "odd" and 5
♦ "even," then that might work.
"Gibberish in, gibberish out. A trial judge, three sets of lawyers, and now three appellate judges cannot agree on what this law means. And we ask police officers, prosecutors, defense lawyers, and citizens to enforce or abide by it? The legislature continues to write unreadable statutes. Gibberish should not be enforced as law."
-P.J. Painter.