Posted 2009-May-01, 11:38
Over 3
♣ I would have bid either 4
♦ showing diamonds and a major or 4
♣ showing any two-suiter, depending on my agreements.
Edit: I have also played a third option: 4
♦ as both majors and 4
♣ as diamonds + a major.
This post has been edited by gnasher: 2009-May-01, 11:39
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn