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BAM bidding decision

#1 User is offline   Apollo81 

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Posted 2009-February-11, 11:57

r/r BAM

Kxx
K9x
JTx
JTxx

(1♦)*-Dbl-(1♥)-p
(1N)-Dbl-(2♦)-?

*could be short
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#2 User is offline   JLOL 

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Posted 2009-February-11, 12:18

double even though 3N could be the winner I'll just take the cash.
New website: http://www.justinlall.com
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#3 User is offline   gnasher 

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Posted 2009-February-12, 05:42

I would have bid 1NT on the previous round.
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
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#4 User is offline   Apollo81 

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Posted 2009-February-13, 10:12

no one else wants to try this one?
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#5 User is offline   uday 

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Posted 2009-February-13, 10:14

I might have X'd the 1st time to show values. I think J is right - X sounds good ( i'd lead a trump) -- try for 200.
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#6 User is offline   awm 

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Posted 2009-February-13, 13:24

I would also have bid 1NT on the previous round.

Now I am somewhat concerned about their diamond fit. Partner's doubles could easily be a hand short in diamonds (he did make a takeout double after all), and they could easily have a nine-card fit there. I don't think partner will remove my double of 2♦ if he holds AQxx AQxx x KQxx or the like and 2♦ could well make (any in any case we probably make 5♣ and 2♦-1 won't be a great result). On the other hand, having failed to show my values on the first round of bidding I don't feel like I can exactly pass now. I suppose double might be the least of evils (it also depends a bit on how silly opponents are about bidding diamonds opposite a "short" diamond and how likely partner is to double twice with an "off-shape" hand -- my feeling is a lot of precision pairs are actually quite silly in this respect).
Adam W. Meyerson
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#7 User is offline   Apollo81 

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Posted 2009-February-13, 15:29

Either double or 3NT will work well; partner has AJT9 ATx Qx AKxx. 3NT was the contract at the other table, where 1NT was overcalled and the OP's hand invited game.

Double gets the 800 though.
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