New Counting system of Honor Card Point
#1
Posted 2008-March-13, 22:57
Ace:=4HCPs;
King:=3HCPs;
Queen:=2HCPs;
Jack-10:=1HCP;
Queen-Jack with any card else:=3HCPs;
Might be called as 836/683 HCP Counting system;
All HCPs in a deck are 36HCPs to 40HCPs;
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#2
Posted 2008-March-13, 23:05
Why can't I just look at my hand and say, "I want to open this" or "I think this hand is good enough to bid game" without worrying about how many "points" I have?
Furthermore, I do not understand what player base an alternative point sequence is trying to reach. An expert does not need a funny point counting scheme to tell him what to do. An advanced player's judgment is better-suited to decide what to bid as opposed to a mechanical point counting scheme, and if he is wrong, he should be working on his hand evaluation so that he can become as good as the expert at making these decisions. The beginner has way more to learn than a modified point-counting scheme, and I can only imagine how much it will hurt his game to think that silly science is the way to improve.
#3
Posted 2008-March-13, 23:09
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#4
Posted 2008-March-14, 00:12
#5
Posted 2008-March-14, 02:09
I dont agree with ppl saying its worthless.
First of all anyone, from begginer up when read this new system learn that QJX(X) or J10X is a good thing to have, but J or Q alone is not so good, even if not using this system, it will help.
Second counting has an advantage of "judgment" evaluation because its obejective, judging is subjective and you might like your hand because in BBO AK1042 looks like a 6 card suit because of the font. you might like a hand because you got a nice present for your birthday yesterday, not liking the same hand tomorrow.
Ofcourse i dont believe that any counting system can take all parts of hand evaluation into accout, and offcourse we still need judgment, but if someone feels good about using a counting system for parts of evaluation then its good for her.
Lets take this specific example of couting system, all a player should take from it is to do the same counting as he did till today but dont count lone Js, thats all, then counting evaluating same as always.
#6
Posted 2008-March-14, 06:43
So why make point count more difficult when you know it won't improve your bridge?
#7
Posted 2008-March-14, 10:52
More important to teach them the hidden potential of touching honours imho.
Unless explicitly stated, none of my views here can be taken to represent SCBA or any other organizations.
#8
Posted 2008-March-14, 11:55
Let's take the argument: "I look at my hand and say its an opener because it is 5-5 and has 10 HCP". You could come up with a rule set of which hands you open and which hands you don't open and come up with a formula based on it. You have just created a point count system. Now true it may not be solely based on HCP, but you still are defining a count. Just like losing trick count, Zar Points, etc. People are trying to redefine the point count system, so there is less of a variance since although we are taught 26 HCP makes a game, we know there are plenty of hands without 26 HCP which make game.
Unless you do come with some basis for counting, how can you make sure you will open the same hand tomorrow? Also, as your partner, it is important that I know your basis for counting, so my hand may fit in context.
The only problem with QJ being given worth extra value is that in a very long suit it becomes much less important. I think Kaplan had a whole formula on suit strength
#9
Posted 2008-March-14, 12:47
#10
Posted 2008-March-14, 13:03
Things that are much more subjective:
1. Aces are good and are worth slightly more than their count.
2. Queens and Jacks are worth slightly less.
3. Honors in combination are worth more than honors alone.
4. Honors in my long suits are worth more than honors in my short suits.
5. Fitting honors in my partner's suit are worth more than honors in a side suit.
6. Honors sitting under a suit bid on my left are worth less than honors in a side suit, whereas honors sitting over a suit bid on my right are worth more.
7. Shortness is worth more, the bigger the fit I have with partner.
8. Intermediaries are important and should be considered as to how well you like the hand, especially if they are in your long suit.
9. Certain shapes don't play as well (4333, 4441, etc) whereas certain shapes typically play well (5431, 6421, etc).
10. Hands that are misfits with partner should be downgraded.
etc. etc.
They don't even need to have it clarified in terms of point count in my view. I think they should simply bid according to "I like my hand so should bid more" or "I don't like my hand so should bid less."
#11
Posted 2008-March-15, 02:48
and I must emphasize that J without the near neighbor,not only lone Jack mught be counted as 0 HCP;
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#12
Posted 2008-March-15, 06:21
#13
Posted 2008-March-17, 01:01
2008-01-11 21:05:43
AKJ(without 10):=7;
KQJ:=6;
AQJ:=7;
AJ(without 10):=4
KJ(without 10):=3
QJx:=3
2008-01-08 20:06:29
A:=4;K:=3;Q:=2;
others:
(1)3HCPs for Q-J & any card(A,K,10,9,8,7,6,5,4,3,2);or
(2)1 HCP for J-10;or
(3)3HCPs for other 4 Jacks in hand; or
2HCPs for other 3 Jacks in hand; or
1HCP for other 2 Jacks in hand;
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#14
Posted 2008-March-17, 04:34
A = 4.5
K = 3
Q = 1.5
J = 0.75
T = 0.25
(A = KQ = 3Q; K = 2Q; Q = 2J; J = 3T)
In NT contracts, it is more like:
A = 4
K = 2.8
Q = 1.8
J = 1
T = 0.4
(A = 2Q+T; K = Q+J; Q = J+2T)
Unfortunately you don't always know whether you will end up in a trump or NT contract... The usual judgement, like honor concentration and long suits, applies as well.
Steven
#15
Posted 2008-March-17, 22:59
so...
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#16
Posted 2008-March-17, 23:07
A = 2e
K = pi
Q = (pi+e)/3
J = pi - e
T paired with either Q or J has value = 2i
#17
Posted 2008-March-18, 11:06
matmat, on Mar 18 2008, 12:07 AM, said:
A = 2e
K = pi
Q = (pi+e)/3
J = pi - e
T paired with either Q or J has value = 2i
No, no, no. An Ace paired with a second ace in the same suit=i
#18
Posted 2008-March-18, 12:51
joshs, on Mar 18 2008, 12:06 PM, said:
Crap. what was i thinking. Of course!
#20
Posted 2008-March-18, 22:26
matmat, on Mar 18 2008, 12:07 AM, said:
A = 2e
K = pi
Q = (pi+e)/3
J = pi - e
T paired with either Q or J has value = 2i
Very good!
U remind me another game of playing cards which we were enjoying when I was a child;
now,
A:=5;
K:=3;
Q:=2;
J:=half;
This post has been edited by civill: 2008-March-18, 22:28
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