HeartA, on Oct 14 2005, 08:05 PM, said:
2♣ without xyz, 3♣ with xyz.
Oddly enough, I would reverse these bids, bidding 2♣ playing xzy and 3♣ when not (following bridge today method of xyz) where 3♣ playing xyz is to play, hence no such bid is possible to me.

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