MickyB, on Sep 20 2005, 04:55 PM, said:
Agreed Hannie, this is a 2♥ bid playing 2/1. It is just too hard to express your values otherwise.
Now for something completely different (aka an alternative view).... I will try to express it using ZAR but you guys already know this without ever mentioning ZAR.. what do you do with 11 misfit?
What would ZAR say? Partner has at least 5
♠, we have one, that is a difference of four. We have six hearts, partner rates to have on average 2 or 3, that is difference of 4 or so. And if partner is 5-2 in the majors, there is at least one more difference in the minors, if 6-2 or 5-3, difference of at least two in the minors. So his "mifit points" are in the range of 7 or 8 points.
Can you use this? Perhaps. You have 29 ZAR points (11 hcp, 3 Control points, 15 DP). So your partners 25 minimum (he opened
♠), your 29 comes to a minimum of 54 points. This suggest game. On the other hand, if partner lacks hearts, you have to subtract the misfit points (average 8), giving a total of 54-8 = 46.
But instead of subtracting the misfit points, you can add them if (and only if), you have a superfit. If you think this way, you might play 1S-3H as invitational with 6 card suit. This way, if your partner happens to hold a heart fit, he will carry on. Without it, he will pass. The DANGER here, however is if partner has
♠ and
♣. You could have a modest
♣ fit (4-4) or a superfit (5-4). Does that make a difference? Well, without superfit, no, not really. If partner has 4
♣, according to zar, you get 2 pts for
♣KQ, and 2 points for x of spades (bringing your total to 31). To make 5
♣, your partner needs only 26....So, if you bid 3
♥, you risk your partner passing with 4 or 5
♣ and a minimum hand, which might be just what you need for game in clubs.
So, according to ZAR analysis, you should bid 3
♥ when you know you have no
♣ fit, and bid 2
♥ when you have one. Sigh. Fortunately, I have learned from the foot of the master (Ritong) that the right bid with north is 2
♠ (minimum hcp with five plus spades and four plus clubs). So right or wrong, my auction would be...
2
♠ - 2NT (asking, gf - we might be 6=3 in
♥)
3
♣ - 5
♣ (3
♣ = five clubs), 5
♣, well, it turns out not to be so wonderful)
Pass
The ZAR point counters would say, partner wth 5-5 in blacks gives you at least 10 misfit points, to go with your original 29 (count fit or misfit points, not both), that comes to 39+25 for partner or minimum 64.. why not blackwood, why not slam. Another advantage of Roman 2
♠. It has limited value. Partner with 5-5 (or better), has at least 14 DP, if he has two ACES (12 more) for 26 total, he could not have more than one king. There just isn't enough room in has hand for enough honors (
♠AQxxx
♥x
♦Kx
♣Axxxx for example is maximum he could hold in hcp with this bid. So I would try game.
BTW, since I play this roman 2
♠ bid, if partner opened 1
♠, I WOULD bid 3
♥ invitational with this hand. The reason being, if partner has
♣ he has extra values, and he will bid again, and if he has
♥ fit, he will not pass. The Roman 2
♠ provides some safety in the 3
♥ bid with this hand..
reverse the minors, and, sigh, I would have to respond 2♥ as well.... :-(