Usually, RHO has 6 and LHO has three for the raise. One of them could be joking around, but I've found this to be true 75% of the time.
Pard's most likely shapes are: 0-4-5-4 and 0-4-4-5. Other possibilities are 0-5-4-4, and some sort of 5-5 or 6-4's. Lets set the clubs at 4, but I think thats a best case situation for the passers. 18 TT and no adjustments as far as I can see. The 10♠ is a possibility, but surely that card is exposed once I pass the double. So unless declarer has specifically the ♠AKJ, the ♠10 is immaterial. So, the spade 10 should be worth about a 1/3 trick, but certainly the chances of greater than a 9 card club fit more than offset this.
The knowledge of a 9 card club fit is good news for 3N, as it is not only a source of tricks, but also translates into entries to the closed hand for red suit finesses that will likely work. As far as the power required to make 3N - pard could have a good 15, but could also have 19 - 20. LHO should raise somewhat randomly with 3 trumps holding a yarb, but also holding a good 10-11 too, so we are at a guess to an extent. Additionally, RHO is somewhat undefined.
I too, have never heard of translating LOTT into NT contracts. Helene - can you elaborate on this?
If we are making 4♣, 3♠ is -1 (good for the 4♣ bidders, bad for the passers and the 5♣ bidders, and probably bad for the 3N bidders). If we are making 5♣, 3♠ is -2. Again, bad for the passers, possibly bad for the 4♣ bidders (if pard doesn't raise) but probably good for the 3N bidders.
If 5♣ is making 6, this is the only scenario where the pass seems to pay off with +500 against the +420's. Although I would argue in this case, 3N is getting +630, beating the club bidders.
SO its close. If you think your opponents are jerking you around (or are younger than 25

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