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no control in the "4th" suit preempted

Poll: no control in the "4th" suit (20 member(s) have cast votes)

Your call?

  1. Pass (0 votes [0.00%])

    Percentage of vote: 0.00%

  2. Double (0 votes [0.00%])

    Percentage of vote: 0.00%

  3. 4NT (4 votes [20.00%])

    Percentage of vote: 20.00%

  4. 5D (5 votes [25.00%])

    Percentage of vote: 25.00%

  5. 5NT (0 votes [0.00%])

    Percentage of vote: 0.00%

  6. 6D (10 votes [50.00%])

    Percentage of vote: 50.00%

  7. 7D (0 votes [0.00%])

    Percentage of vote: 0.00%

  8. Other (1 votes [5.00%])

    Percentage of vote: 5.00%

  9. Abstain (would have bid inverted 2D or 3S splinter) (0 votes [0.00%])

    Percentage of vote: 0.00%

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#21 User is offline   MinorKid 

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Posted 2014-February-14, 08:42

View PostZelandakh, on 2014-February-14, 04:59, said:

Ignoring the auction, the chance of one or more honours from 3 cards is 1 - ((8.7.6)/(13.12.11)) ~= 80%. I assume your 29% is the calculation for no picture honour (with odds of one appearing being ~71%) but even if you are calculating something else entirely I am not absolutely certain why this calculation is relevant. As an example, the actual hand had no spade honour from 3 but no play for 7. Add the J and change K to the ace and the grand makes. So how does this bring us forward?

Just as an aside, the chance of drawing an honour from a single card is 5/13 = 38% so something must have tipped you off that 29% could not be correct for 3 cards surely?!


Sorry Wrong calc. 71% is right :huh:
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