Posted 2005-January-22, 19:32
At the time you must make the decision, there are only 2 cases that must be considered - J32 opposite Q, and 32 opposite QJ. Originally, there were 8 cases of a 3-1 split, with a total a priori probability of 49.74%, and 6 cases of a 2-2 split, with a total probability of 40.70% (Encyclopedia of Bridge, Mathematical Tables). The relative probabilities for the two remaining cases hold. Therefore, the 2-2 split is more likely. However, RHOs best strategy is to randomly play the Q or J from the QJ doubleton. (If he always plays the Q, you are entitled to this information.) The probability of interest is that he held the QJ AND he played the Q. If he follows the optimum strategy, this is only half as likely as holding the QJ originally, so your best strategy is to play for the 3-1. It comes to about 64.7%. I remember reading an article by Jeff Rubens about what happens when he follows a non-optimum strategy, and would like to hear if anyone can identify it.