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3rd fav 7-5

#1 User is offline   Fluffy 

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Posted 2013-January-23, 03:17

MPs

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#2 User is offline   wank 

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Posted 2013-January-23, 03:23

5 - interesting place to put the thread btw
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#3 User is offline   lycier 

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Posted 2013-January-23, 03:28

View PostFluffy, on 2013-January-23, 03:17, said:

MPs



西班牙国世界大师Fluffy应邀来到我们华人论坛出题,题面的意思是:
在第三家,你持有7-5套,如何开叫?
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#4 User is offline   nathan2008 

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Posted 2013-January-23, 03:45

5D 不解释
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#5 User is offline   arter 

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Posted 2013-January-23, 04:01

前两家低花不会太长。也没有高花弱二的牌面。虽然如此。我还是会叫5D。毕竟局况有利。敌人的高花配合让人压力太大了。
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#6 User is offline   lycier 

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Posted 2013-January-23, 04:13

View Postarter, on 2013-January-23, 04:01, said:

前两家低花不会太长。也没有高花弱二的牌面。虽然如此。我还是会叫5D。毕竟局况有利。敌人的高花配合让人压力太大了。


如果同伴持有:
:XXXX

:XXXXX

:K

:KQJ


喂,哥们儿~,6是铁打的。
所以,我愿意开叫1.
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#7 User is offline   the_clown 

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Posted 2013-January-23, 04:20

I would try 4 at MP. I am not too worried about missing game and 4 gives them the chance to go really wrong. Usually when I open 5 all they can think of is double and I get a score at the bottom of the field.
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#8 User is offline   nathan2008 

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Posted 2013-January-23, 04:29

View Postlycier, on 2013-January-23, 04:13, said:

如果同伴持有:
:XXXX

:XXXXX

:K

:KQJ


喂,哥们儿~,6是铁打的。
所以,我愿意开叫1.


呵呵。。。 作为一个数学工作者,从数学上说,你说的特例当然存在,但是更多情况是敌人有一个高花配合,所以我们需要算的是 他的期望值。不是吗? fantoni nunes 也不能保证他们每副牌赢。但是他们能保证他们的体系在绝大多数情况下占优,就是说他们的期望值大,这就足够了。 我们要玩的是大概率,而不是老是去拘泥于这种小概率。 开 5d 期望值肯定要大于开1d。 对我来说,桥牌只是简单的数学。。。
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#9 User is offline   nathan2008 

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Posted 2013-January-23, 04:39

View Postlycier, on 2013-January-23, 04:13, said:

如果同伴持有:
:XXXX

:XXXXX

:K

:KQJ


喂,哥们儿~,6是铁打的。
所以,我愿意开叫1.


而且就算你真的开1d 了。我也不相信你能叫到 6d 。你打算怎么叫? 还是生活得简单点吧。。。直接 5d 干脆。
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#10 User is offline   lycier 

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Posted 2013-January-23, 04:51

View Postthe_clown, on 2013-January-23, 04:20, said:

I would try 4 at MP. I am not too worried about missing game and 4 gives them the chance to go really wrong. Usually when I open 5 all they can think of is double and I get a score at the bottom of the field.


这位朋友的贴子大意是:
打mp,我愿意开叫4。我是不太担心丢局的问题,而这样开叫的好处是给敌方一个真正犯错误的机会。通常当我决定5阶开叫,敌方所考虑的是加倍,我也因而会得到一个底分。
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#11 User is offline   lycier 

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Posted 2013-January-23, 05:15

View Postthe_clown, on 2013-January-23, 04:20, said:

I would try 4 at MP. I am not too worried about missing game and 4 gives them the chance to go really wrong. Usually when I open 5 all they can think of is double and I get a score at the bottom of the field.


However, a hard thing is we play namyats convention,so no way to open 4Posted Image
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#12 User is offline   madongjun 

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Posted 2013-January-23, 05:20

我会叫1,然后在竞叫过程中,叫出草花,最后可能是以低花牺牲对手的高花,运气好的话,能赚取一个加倍的低花局分。
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#13 User is offline   cqwbc 

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Posted 2013-January-23, 06:14

我支持开叫4
我来谈谈我开叫4的理由,就是为了有机会更好地描述套,非等长畸形牌(7-5牌型甚至8-5牌型),开叫4就是给opp空间叫出4M,我再叫5,这样叫同伴是不会理解为6-5牌型了,也为PD更好地估值牌。如果开叫5pd在非上的牌值如何估值呢?开叫1最大问题是opp迅速达到4M后你再叫5C是6-5还是7-5牌型,pd很为难,估算输张就会出现偏差。综上所述,我支持开叫4
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#14 User is offline   zyp163 

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Posted 2013-January-23, 07:31

I tend to bid 2C.tell pd I would play this hand but opps.
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#15 User is offline   lycier 

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Posted 2013-January-24, 01:10

View Postzyp163, on 2013-January-23, 07:31, said:

I tend to bid 2C.tell pd I would play this hand but opps.


You meanings is you want to open 2? I disagree that style with 6 loser.
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#16 User is offline   wuhuan 

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Posted 2013-January-24, 02:30

英语很差看不懂但还是参与一下————
叫4D不会被误会为纳米亚次约定转4S吗?
叫1D很可能叫不到愿望中的满贯,
中庸一点还是叫5D。
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#17 User is offline   FyxShen 

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Posted 2013-January-25, 03:52

即使4D不是约定叫,也还是5D更好。

压力和猜断留给对手,不要留给自己,特别是白对红的第三家。

这牌如果1D开叫,假设你准备跟到5D,那么对方5M之后,拍还是不拍就不好办了。
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#18 User is offline   Fluffy 

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Posted 2013-January-25, 04:14



5X +200, 6 +920 (1090). ATB (Assign the blame)
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#19 User is offline   3ntmk 

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Posted 2013-January-25, 04:49

我非常遗憾,大师为什么这么 快就给出答案。强烈建议另外发帖给出答案。

希望大家不要嘲笑我的巧合。我完全考虑了自己的思想和大家提到的可能会遇到的困难,但正如答案,考虑进去了。

大家给出了不同的开叫方式。但我很疑惑,难道牌面不是非常准确,合格的1D开叫吗?因为多了长度,有个牌型,会动摇根本吗?开叫1D保留了所有的机会。正如数学家所言,这是个数学游戏:你不可能永远指望别人犯傻、犯错,力争叫好自己的牌,才是方向。

开叫1D,再叫1-2次C,基于如此的长度,只要C少许的支持就可以保持竞叫,D是独立套无需支持。我会一直在配合的C或不配合的D上竞叫至6阶,除非同伴惩罚对方的5阶高花定约(对方单有局)。怎么会是本手牌加倍5H?
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#20 User is offline   cqwbc 

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Posted 2013-January-25, 05:33

View Post3ntmk, on 2013-January-25, 04:49, said:

开叫1D,再叫1-2次C,基于如此的长度,只要C少许的支持就可以保持竞叫,D是独立套无需支持。


如此畸形的牌 opp会给你叫2次机会吗?
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