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Pairs, can you reach 7N with certainty

#1 User is offline   Cyberyeti 

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Posted 2012-December-09, 17:24

Pairs, NS vul

E deals - E passes, S passes, W opens 1 over to you ...

We bid this in fairly prosaic fashion to 7 for most of the matchpoints in a poor field (1)-x-3-4(KC)-5(2w/o)-7.

There was a sequence we might have used and think we'd have got right at the table to 7N, but the question is how can N be sure his clubs cash. In this field you don't want to bid 7N opposite xx.
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#2 User is offline   broze 

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Posted 2012-December-09, 17:35

Some play 6 over 5 as asking for a doubleton/singleton/queen. After receiving a negative response you can go for 7NT, knowing partner has 3 small. Would make me chuckle at the table. :)
'In an infinite universe, the one thing sentient life cannot afford to have is a sense of proportion.' - Douglas Adams
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#3 User is offline   bigbenvic 

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Posted 2012-December-09, 23:03

Sadly no, 7 is the limit I'd be able to reach.
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#4 User is offline   Cyberyeti 

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Posted 2012-December-10, 02:25

View Postbroze, on 2012-December-09, 17:35, said:

Some play 6 over 5 as asking for a doubleton/singleton/queen. After receiving a negative response you can go for 7NT, knowing partner has 3 small. Would make me chuckle at the table. :)

What we play is that 6 says basically I have the K or Q, have you got the other one.

We reckoned using that, getting the inevitable negative 6 then bidding 7 anyway would suggest something like this going on, either AK 7th or AKQ 6th looking for 7N.
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#5 User is offline   Zelandakh 

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Posted 2012-December-10, 03:09

As broze points out, the answer is to play SSAs.
(-: Zel :-)
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#6 User is offline   Fluffy 

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Posted 2012-December-12, 03:33

I woun't even be able to find 5th heart, let alone third club.
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#7 User is offline   gnasher 

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Posted 2012-December-12, 04:59

View PostCyberyeti, on 2012-December-10, 02:25, said:

What we play is that 6 says basically I have the K or Q, have you got the other one.

We reckoned using that, getting the inevitable negative 6 then bidding 7 anyway would suggest something like this going on, either AK 7th or AKQ 6th looking for 7N.


You also have ...6-6-6 and ...6-6-7. That should be enough room to cover all of AKJxxxx, AKQxxx and AKQxx.
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
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