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逼叫性1NT应叫后(rediscovering 1NT forcing) From Chamaco

#1 User is offline   zyp163 

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Posted 2012-September-30, 21:30

Chamaco


in the book "For experts only", edited by the Granovetters, there is a chapter by Kokish about "rediscovering 1NT forcing".
在“仅为专家”书中,有一章关于库克什“1nt逼叫后的再寻”。
One of the issues he addresses is how responder could be able to bid (discriminate) weak and goodish hands.
他处理的问题之一:如何区分弱还是强牌。
He suggests the use of some specific sequences, which at first sight might seem unnatural, but that after some thinking I was able to remember under the "lebensohl" heading.
他建议使用一些看起来像非自然的具体序列,像“莱本索尔”一样记忆即可。
The first "free" suit at the 2 level except a preference to opener's major, would be Lebensohl, forcing a puppet to next suit, followed by pass/correct.
在二阶首先是偏向于应叫开叫者的开叫花色,然后就是莱本索尔,通过一个傀儡式逼叫,然后PASS或者纠正。

There are a few sequences (when opener openes 1S and rebid H or S) when no "Lebensohl" is available, as 2NT is the only step.
It is conceivable, IMO, to use 2NT as Leb even in that case, since when we do have a balanced invite, we can play 3M in a 6-2 fit
有几个序列(当开叫者开叫1S并且重叫H或者S时),无法使用“莱本索尔”,这是可以理解的,因为我们可以做一个平衡邀请,可以尝试6-2配合的3M。

Some examples
一些例子:
1S:1NT:2C
....-2D "Leb"= Puppet to 2H, then P/C(傀儡至2H然后不叫或者纠正)
....-2H= normal
....-2S= 8-10 with doubleton spades (weak 3 card raise would go via 2D"Leb")
....-2NT = natural invite 自然邀请
....-3x = natural invite (the weak hand would go via leb)


1S:1NT:2D
....-2H "Leb"= Puppet to 2S, then P/C
....-2S= 8-10 with doubleton spades (weak 3 card raise would go via 2H"Leb")
....-2NT = natural invite
....-3x = natural invite (the weak hand would go via leb)

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It seems to me that this fits well in the 2/1 version whenre 2/1 is absolute GF, since it becomes easier to show the invitational 1-suiter without bidding a 2/1.
我感觉在2/1绝对逼局时,这个序列很适合,因为他很容易显示邀请实力的一手牌。
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#2 User is offline   cqwbc 

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Posted 2012-October-01, 09:14

不用Gazzilli方式的可以参考使用
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