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GW stac #1

#1 User is offline   rduran1216 

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Posted 2011-August-22, 17:25



Your bid?
Aaron Jones Unit 557

www.longbeachbridge.com
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#2 User is online   mike777 

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Posted 2011-August-22, 17:29

I will risk 3h.
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#3 User is offline   aguahombre 

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Posted 2011-August-22, 19:38

six losers. I think if CHO can cover 3 of them she might raise unless she thinks very little of my direct overcalls.
"Bidding Spades to show spades can work well." (Kenberg)
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#4 User is offline   wyman 

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Posted 2011-August-22, 19:42

not good enough for 4H, too suit-oriented for 3N

3H for me.
"I think maybe so and so was caught cheating but maybe I don't have the names right". Sure, and I think maybe your mother .... Oh yeah, that was someone else maybe. -- kenberg

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#5 User is offline   phil_20686 

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Posted 2011-August-22, 20:04

I would bid 4H. This is a very good hand.

Feels heavy for 3H, but not disastorously so. The difficutly is always when partner has a singleton and a 9 count or so, he will not find a raise. I think you should stretch to game when your intermeadteads (the JT) are so good. Also, with so many keycards you can certainly stand a raise to slam.
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#6 User is offline   Free 

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Posted 2011-August-23, 01:55

Can I bid 3.5? No? Then 3 for me.
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#7 User is offline   jmcw 

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Posted 2011-August-23, 05:39

Full value for a 3 call.

3 = 10
4 = 4
Pass = 2
3NT = 1
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#8 User is offline   farrnbach 

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Posted 2011-August-23, 05:47

Team: 4 (ok, heavy, I agree)
Pairs: 3
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#9 User is offline   mycroft 

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Posted 2011-August-23, 09:58

1) I play heavy overcalls of preempts. That loses in many cases, but not this one.
2) This is nicely acey, but I see three black suit losers and two red suit losers (assuming that the HQ can be picked up). As others have said, if partner can cover enough losers, she'll raise. If responder doesn't raise, that club loser is guaranteed. I'd be more likely to bid 4 if one of my spades was a club, for that reason.
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#10 User is offline   whereagles 

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Posted 2011-August-23, 12:09

Bad shape, so 3 seems better than 4, though since this is a problem 4 is probably the winner :P
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#11 User is offline   rogerclee 

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Posted 2011-August-24, 12:51

3H is really poor to me. It seems like conventional wisdom is to make 3H extremely wide ranging and to have 4H show basically 8.5 tricks in hand. I don't know why this is the case, and we can easily expect to make 4H opposite a lot of random 8 counts without 3 hearts, so why not just bid what you think you can make?
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#12 User is offline   gnasher 

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Posted 2011-August-24, 16:29

3NT, because I think it needs less than 4.
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
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#13 User is offline   aguahombre 

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Posted 2011-August-24, 16:47

View Postgnasher, on 2011-August-24, 16:29, said:

3NT, because I think it needs less than 4.

If that post came from me, I would give it a big LOL. But, coming from Andy, I need to think about it and try to get over the fact that I can only duck one club and am open in spades.
"Bidding Spades to show spades can work well." (Kenberg)
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#14 User is offline   nigel_k 

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Posted 2011-August-24, 16:55

View Postrogerclee, on 2011-August-24, 12:51, said:

3H is really poor to me. It seems like conventional wisdom is to make 3H extremely wide ranging and to have 4H show basically 8.5 tricks in hand. I don't know why this is the case, and we can easily expect to make 4H opposite a lot of random 8 counts without 3 hearts, so why not just bid what you think you can make?

I agree and prefer 4 to 3NT.
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