JLOGIC, on 2011-August-14, 11:40, said:
Even though west is more likely to have the diamond jack, it doesnt make a first round finesse in diamonds necessarily the best line, losing to stiff jack on your right is a big deal.
Basically you are picking up 3 combinations of Jxx on your left, and losing to 3 combinations of Jx on your right, and 1 combo of stiff jack. So it is 4 combinations to 3, meaning you need LHO to be MUCH more likely to hold the jack. Obviously when they're 2-2 it's equal who has the jack, so really you need them to be MUCH more likely to be 3-1 than 2-2 to overcome that deficit. <emphasis added>
Here I tried to answer the question, is the chance WEST holds 3 diamonds high enough to overcome the 3 to 4 ratio Justin correctly points out. BTW, the combination math shown above is correct. One might realize that there are 11 such combinations (not 7), but singleton jack on side (one combination) and doubleton jack on side (three cases) (7+4=11) either line works, so Justin correctly left those lines out. 3 to 4 is hard odds to overcome. Justin then adds the key statement: you need them to be MUCH more likely to be 3-1 than 2-2 to overcome that deficit.
So this gets to where we have to consider what are the odds WEST has three diamonds versus two diamonds? There are three ways to consider this situation. First, all theoretically possible holdings for West. Second potentially likely (on the bidding) holding for west. And, finally, all potentially likely holdings for West that will allow us to find a successful line of play. These are three different subsets, but we will start at the END of trick two where WEST shows out on hearts. But for this discussion the one thing we know,
East has six hearts and WEST has only one. These are the possible distributions that WEST could hold.
Case one: all theoretical possible West hands when East has 6 hearts, west one (given they have a total of 9
♠, 7
♥, 4
♦ and 6
♣ between their two hands).
9=1=3=0, 9=1=2=1, 9=1=1=2, 9=1=0=3, 8=1=4=0, 8=1=3=1, 8=1=2=2, 8=1=1=3, 8=1=0=4, 7=1=4=1, 7=1=3=2, 7=1=2=3, 7=1=1=4, 7=1=0=5, 6=1=4=2, 6=1=3=3, 6=1=2=4, 6=1=1=5, 6=1=0=6, 5=1=4=3, 5=1=3=4, 5=1=2=5, 5=1=1=6, 4=1=4=4, 4=1=3=5, 4=1=2=6, 3=1=4=5, 3=1=3=6, 2=1=4=6, a total of 352,716 hands.
In these holdings, West will hold 3
♦s 39.73% of the shapes, and 2
♦ 35.76% of the time. However, we are certain that West does not have either 9 or 8 spades, and I think we can be reasonable certain that he does not have 7 spades. So we can remove those hands. We are also sure that East does not have 7 or 6 spades, so we can remove those hands as well.
Case two: Holdings for West consistent with the bidding
9=1=3=0, 9=1=2=1, 9=1=1=2, 9=1=0=3, 8=1=4=0, 8=1=3=1, 8=1=2=2, 8=1=1=3, 8=1=0=4, 7=1=4=1, 7=1=3=2, 7=1=2=3, 7=1=1=4, 7=1=0=5, 6=1=4=2, 6=1=3=3, 6=1=2=4, 6=1=1=5, 6=1=0=6, 5=1=4=3, 5=1=3=4, 5=1=2=5, 5=1=1=6, 4=1=4=4, 4=1=3=5, 4=1=2=6,
3=1=4=5, 3=1=3=6, 2=1=4=6 a total of 269,010 hands
Once we remove the wildly unlikely distributions based upon the bidding, we find the West will hold 3
♦ 45.03% of the time, and 2
♦ 33.44% of the time. So we begin to get to the question is this increase enough to overcome the 3 to 4 odds Justin mentioned? And what about case three?
Case three: Holdings for West consistent with the bidding where you can make the hand if you guess right.
9=1=3=0, 9=1=2=1, 9=1=1=2, 9=1=0=3, 8=1=4=0, 8=1=3=1, 8=1=2=2, 8=1=1=3, 8=1=0=4, 7=1=4=1, 7=1=3=2, 7=1=2=3, 7=1=1=4, 7=1=0=5,
6=1=4=2, 6=1=3=3, 6=1=2=4,
6=1=1=5, 6=1=0=6, 5=1=4=3, 5=1=3=4, 5=1=2=5,
5=1=1=6, 4=1=4=4, 4=1=3=5, 4=1=2=6,
3=1=4=5, 3=1=3=6, 2=1=4=6 a total of 189,924 hands
From this mixture we find 3
♦ with West 57.38% compared to 2
♦ at 42.62% (of course, we made two assumptions. One you can't make with 4=0 split, two, you can't make if West has singleton diamond and singleton heart). I happen to also believe we can also remove the 4=1=3=5 hand because for the life of me, I can not find a way to make it with that pattern. That leaves us with these hand patterns.
WEst hand patterns
6=1=3=3 47040 24.77%
6=1=2=4 52920 27.86%
5=1=3=4 52920 27.86%
5=1=2=5 31752 16.72%
4=1=2=6 5292 2.79%
This shows the percentage of 2=2 splits as 2.79+16.72+27.86 = 47.37%, the chance of a 3=1 split is 52.63%. So the bottom line is this good enough to overcome the 3 to 4 combination ratio? Well in all the 2=2 splits with these shapes, AK of diamonds wins. That is 47.37%. In addition, 1/4 th of the 3=1's, cashing the AK of diamonds will work because the Jack falls. This adds 0.25 * 52.63 = 13.16% for a total of 60.53% of the hands where you can make it, you will by the line of cashing the AK of diamonds. Taking the first round finesse works when the Jack is not singleton on 3-1 splits (0.75*52.63% = 39.47%) plus half of the 2=2 splits (when jack is onside) which is 0.5 x 47.37 = 23.68%), for a total of 63.16%.
So it seems if I excluded the right hand types, and correctly calculated which hands make and don't make with the various lines of play, first round diamond hook is slightly better than cashing the AK of diamonds.
If you are really going to get into factoring unlikely hand patterns (like West having 7, 8 or 9 spades or East having 7 or 6 spades), you might want to consider how likely it is that West will hold 6S's. If you decide it is highly unlikley, you can drop the two patterns with six spades. If you think he is about 50-50 to overcall with six spades, you could cut the hand frequency with 6 spades in half. Either change would increase the frequency of WEST having three diamonds because of the two hand patterns where West held six spades the frequency of 2
♦ holding is higher than 3
♦ on those hands. Thus increasing the success rate of the first round diamond finesse.
This last case is what I did for my earlier answer. I figured West almost surely held five spades on this auction, so I only dealt with the two hand patterns: 5-1-3-4 and 5-1-2-5, in deciding what to play. If you don't want to eliminate the possibility of six spades with WEST, you still get close to the same answer. If you are going with the diamond finesse, a key part is NOT to cash the diamond ACE trying to drop the singleton JACK offside. The reason is that when WEST is 5=1=3=4 you can only afford to pull two rounds of trumps, then you need to take the ruffing heart finesse (if east doesn't cover pitch your spade). If you cashed your high diamond, WEST will overruff and cash a spade. You have to ruff with the diamond honor, then ruff a club, and pitch your spade on the the good heart. West gets his diamond jack, but that is the last trick for the defense.
Anyway, both plays are close, the odds for the first round diamond finesse should be a little higher than the 63.13% above and odds of banging AK a little less than above as well, because of decreased real world chances West has six spades on this auction.