Posted 2011-July-21, 01:33
Beware, this post is a bit ridiculous and not particularly salient. I wrote it at whatever AM because I like to watch numbers spin.
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If partner has ♦9, we want to play a diamond. If ♦QT9, we want to play a club. If ♦KT9 it likely doesn't matter which.
♠AJxxx ♦ K6 is enough to overcall, so based on vacant spaces and assuming spades 5-1 (this should be close enough):
♦9 : ♦QT9 is 3:11
If partner has ♦9, it definitely matters that we play a diamond now. If ♦QT9, it only matters to play a club now if declarer has ♣A plus ♥Q without ♣J.
This tips the scale back to ♦9, as ♦QT9 : (♦QT9 - ♣A - ♥Q) is 15*14:6*5, i.e. 7:1. This makes ♦9 a favorite by roughly 2:1 over ♦QT9 - ♣A - ♥Q.
So, assuming I haven't said something silly, and it's late, so the odds here can't be good for me, a diamond looks best.
Adding more: Of course, e.g. 1-5-1-6 is not so likely for partner, who would negative double with most hands this shape. I think I discounted this because I'd sleepily decided we'd overcalled (yes, I then overlooked the contradiction when checking ♠AJxxx ♦K6 was enough for declarer's bidding) and that partner wouldn't act red with this hand after our overcall. Without ♣A, it's possible partner passes, but that already puts us back at equity (i.e. loses the 2:1 factor). This makes a club seem right. A low club would then be best since we get a heart trick if declarer wins ♣J, and maybe declarer won't stick in ♣J.
Rather: ♦9:♦9 - ♣A is 15:4, so this puts ♦9-♣A : ♦QT9 - ♣A - ♥Q at roughly 1:2.