edit: a/e pls hide your answers
how do you defend, and why?
#1
Posted 2010-October-20, 17:25
edit: a/e pls hide your answers
#2
Posted 2010-October-20, 17:47
[hidden]♠2[/hidden]
Hey this hidden text thing is cute.
I believe that the USA currently hold only the World Championship For People Who Still Bid Like Your Auntie Gladys - dburn
dunno how to play 4 card majors - JLOGIC
True but I know Standard American and what better reason could I have for playing Precision? - Hideous Hog
Bidding is an estimation of probabilities SJ Simon
#3
Posted 2010-October-20, 19:12
One possibility is that declarer has four clubs to the ace and the ♦T. In that case he can eventually take 2 clubs, 3 diamonds, 2 hearts and 2 spades, unless we can set up 5 tricks for ourselves first. We might do that by switching to a low spade and continuing spades (possibly the jack) when we get in with the second club.
Another possibility is that he has 3 clubs to the ace and the ♠Q. In that case if we switch to spades he might be able to win in dummy, unblock hearts, and use his two hand entries to establish and cash heart tricks.
I guess it's better to cater for the first possibility since in that case our 5 tricks are more certain. In the second case, even though declarer has only 8 tricks on top without the hearts, it's quite possible we'll be endplayed into giving him the ninth anyway.
#4
Posted 2010-October-21, 07:32
edit:
[hidden]hmm, I suppose on the right lie of spades I should switch to one. Maybe that is better ... I can't really tell.[/hidden]
-gwnn
#6
Posted 2010-October-21, 08:02
edit:
"...we live off being battle-scarred veterans who manage to hate our opponents slightly more than we hate each other. -- Hamman, re: Wolff
#7
Posted 2010-October-21, 09:03
-gwnn
#8
Posted 2010-October-21, 12:39
ATT, nothing mattered since partner held 109xx in diamonds and Q8x in spades. But the way to look at it is:
if declarer has Axxx in clubs, he can score 2 club tricks merely by ducking once more. If he has the spade Q, then he has 9 winners and there is nothing you can do....even switching to hearts merely establishs a 4th trick for you (2 clubs, 1 diamond and 1 heart) since declarer will happily concede a diamond.
If he lacks the spade Q, then the danger is that he may be able to score 3 diamond tricks.....if he holds, for example, as little as 10x or xxx. 3 diamonds along with the major AK's and 2 clubs is game.
So you need to establish 5 tricks, and 2 of them have to be in spades. You cannot afford to waste time....if you continue a club, intending to switch next time, you are a trick behind.....he wins the spade, crosses in clubs, cashes a club and hooks a diamond....and your spades are not yet established.
Concern that he can establish the hearts is misguided......he can't have a second entry to the heart suit, unless he holds the spade Q or the diamond 10, and in either of those cases, he has 9 winners (if given time) without the aid of a long heart.
I thought it was a useful hand to show because the solution is (I think) clear once you take a few minutes to assess your goals and how the future play might go. You need to tentatively place cards and assess how the play will go on various assumptions, and then choose the line that offers the best chance of success.
#9
Posted 2010-October-21, 14:06
mikeh, on 2010-October-21, 12:39, said:
That's not necessarily the case - see my last hidden comment above. But overall I agree the spade is more likely to be right.
-gwnn
#10
Posted 2010-October-21, 15:34
#11
Posted 2010-October-21, 16:17
Secondly, if he has 3=5=2=3, a spade switch (usually) still works if partner has the Q or the 10, and if declarer holds Q10 or Q10x in spades, he will almost surely go right in the suit, given that I opened this foot. He rates to hold the heart J....by a margin of 5-3...and dummy has 21 hcp....if he holds spade Q and heart J, he knows that I have at best a truly hideous 4=3=3=3/4=4=2=3/3=4=3=3 12 count with zero Aces, so he'll play me for the spade J.
What it comes down to is the frequency with which any play other than a spade gains (or loses), and I think the odds are overwhelmingly high that a spade rarely, if ever, loses, and is often critical. A club continuation, otoh, never gains in its own right, and often loses.
#12
Posted 2010-October-22, 06:42
mikeh said:
As declarer, I more or less randomly falsecard or not in such a situation. It costs me zero mental energy, and who knows what strange inferences defenders may make? Or what else they may overlook while thinking about it?
mikeh said:
How does partner holding the ten help?
mikeh said:
Agree about the frequency. Basically there is a pretty specific realistic hand type for declarer that requires a club continuation, but many other possible hands require the spade.
-gwnn

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