TimG, on Aug 7 2004, 09:06 PM, said:
hrothgar, on Aug 7 2004, 12:22 PM, said:
Sorry in advance about the formatting. I think that this analysis is correct, but I didn't get nearly enough sleep last night.
A priori, their are 8 distributions that we need to consider
KJ2 - Void = 11%
KJ - 2 = 13%
K2 - J = 13%
J2 - K = 13%
K - J2 = 13%
J - K2 = 13%
2 - KJ = 13%
Void - KJ2 = 11%
Two of those distributions are intrinsically uninteresting.
If a player holds either a Void or a Stiff King under the 7 card suit, things are pretty dull.
Excluding those two cases leaves
KJ2 - Void = 14.47%
KJ - 2 = 17.11%
K2 - J = 17.11%
J2 - K = 17.11%
2 - KJ = 17.11%
Eight cases minus two cases is six cases. Though I imagine you just forgot to include teh 6th in the post since the five percentages shown add up to ~17.11% short of 100%.
I also think your conclusion is right, though how you got there isn't quite explained.
I corrected the original post and added the J - K2 distriubtion.
>I also think your conclusion is right, though how you got there isn't quite explained.
"The proof is left as an exercise to the reader" ???
More seriously:
The only hand that's at all interesting is the one in which defend holds J2 under AQT9876. In this case, the Defender has three viable Strategies:
The "pure" strategy of always playing the 2
The "pure" strategy of always playing the J
The mixed strategy of playing the 2 with probablity X and the J with probability (1-X)
I'm going to start by looking at the set of pure strategies.
In this case, I'm going to assume that the defender ALWAYS plays his lowest card.
Distribution: J2 - K Frequency = 17.1%
Defender's Strategy = Always play 2
Declarer's Strategy 1 = Always play Ace, Payoff = 13 tricks
Declarer's Strategy 2 = Always play Queen, Payoff = 12 tricks
Declarer's Strategy 3 = Always Play 10, Payoff = 12 tricks
Distribution: KJ2 - Void Frequency = 14.47%
Defender's Strategy = Play 2
Declarer's Strategy 1 = Always play Ace, Payoff = 12 tricks
Declarer's Strategy 2 = Always play Queen, Payoff = 12 tricks
Declarer's Strategy 3 = Always Play 10, Payoff = 13 tricks
Distribution: K2 -J Frequency = 17.1%
Defender's Strategy = Play 2
Declarer's Strategy 1 = Always play Ace, Payoff = 12 tricks
Declarer's Strategy 2 = Always play Queen, Payoff = 13 tricks
Declarer's Strategy 3 = Always Play 10, Payoff = 12 tricks
Distribution: 2 - KJ Frequency = 17.1%
Defender's Strategy = Play 2
Declarer's Strategy 1 = Always play Ace, Payoff = 12 tricks
Declarer's Strategy 2 = Always play Queen, Payoff = 12 tricks
Declarer's Strategy 3 = Always Play 10, Payoff = 12 tricks
Distribution: J - K2 Frequency = 17.1%
Defender's Strategy = Play J
Declarer's Strategy 1 = Always play Ace, Payoff = 12 tricks
Declarer's Strategy 2 = Always play Queen, Payoff = 12 tricks
Declarer's Strategy 3 = Always Play 10, Payoff = 12 tricks
Distribution: KJ -2 Frequency = 17.1%
Defender's Strategy = Play J
Declarer's Strategy 1 = Always play Ace, Payoff = 12 tricks
Declarer's Strategy 2 = Always play Queen, Payoff = 13 tricks
Declarer's Strategy 3 = Always Play 10, Payoff = 12 tricks
Now lets consider Declarer's optimal response to this strategy:
If the Defender plays the Jack, then Declarer should insert the Queen.
This strategy breaks even if Defender played Jack from KJ and breaks even if the Defender played from the stiff Jack.
If the Defender plays the 2, then Declarer has three reasonable options:
Declarer can always play the Ace:
Declarer can always play the Queen:
Declarer randomly play either the Ace or the Queen.
Declarer's expected payoff against Defender's pure strategy is indentical with any of these choices. The easiest way to progress to an equilibirum is to note that if Declarer choses to ALWAYS insert the Queen, regardless of what card the Defender plays he won't be any worse off and can't be "fooled" by a false card.