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Non Symmetric Valuation

#1 User is offline   joshs 

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Posted 2010-July-12, 15:48

Construct pairs of hands A and B where:

A is better than B when partner holds's a 10 count.

B is better than A when partner holds a 20 count.

Where better can be measure as Total Point expectation (assume NV) in your best contract over the set of possible hands partner might have, or total trick expectation in your best strain over the set of possible hands partner might have.

What hand types might have this wierd behavior?
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#2 User is offline   awm 

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Posted 2010-July-12, 16:00

How about:

A: xxxxxxx AKx Ax x
B: AKQJxx xxx xx xx

Opposite doubleton spade and a 10-count, A often produces a making 4. Hand B seems less likely to make game, having more losers and flatter shape.

Opposite doubleton spade and a 20-count, A will make game easily, but slam is usually lousy because of spade losers. However, hand B will often produce slam opposite doubleton spade and a 20-count.

The theme of these two hands is that a long bad major suit is potentially a big asset for game bidding, but this sort of hand tends to be lousy for slam bidding unless partner has a good fit, because it's hard to avoid trump losers or to have enough length in a side suit to make slam without the running the major. However, I don't know how much this has to do with 10-count vs 20-count in partner's hand -- it's more that there exist hands which are good for game but not slam.
Adam W. Meyerson
a.k.a. Appeal Without Merit
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#3 User is offline   quiddity 

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Posted 2010-July-12, 16:03

I guess a trivial example would be
A: 13-card solid suit
B: 20-point balanced hand
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#4 User is offline   joshs 

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Posted 2010-July-12, 18:02

Another class of hands:

Consider a 5431 hand and compare:

a. Axxxx Kxxx Kxx x

with

b. Axxxx Kxxx xxx A

opposite the 10 count, the stiff ace doesn't do much in a major suit contract, you rarely have the tempo and controls to
1. stop diamonds
2. unblock the CA
3. return to dummy
4. pitch diamond losers on good clubs

but opposite the 20 count, the stiff ace has much more value since it increasingly likely that you will be able to use the clubs to pitch diamonds, I think opposite the 20 count b becoms the stronger hand.
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#5 User is offline   Dirk Kuijt 

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Posted 2010-July-12, 22:04

(slight thread hijack)

Albert Morehead, many, many, years ago asked this question:

which is the better holding?

QJT9xx

Kxxxxx

The answer is: it depends.

If partner has xx, then the first holding can always be played for two losers (and easily, by just leading the long suit), while the second always has two losers, and that requires 3-2 with the ace onside, and the ability to lead up to the king, and can easily lose four tricks with a 4-1 break;

But, if partner has Axxx, then the first holding still has half a loser (and you need to be able to lead from the QJ), while the second has a loser only 13% of the time, and there are no entry problems in playing the suit.

So, I expect the first would be better opposite a 10 count, but the second better opposite a 20 count.

codo said:

It is a fact that most people here write as if their opinion is a dogmatic fact.

eugene hung said:

My opinion is that this ought to win the award for best self-referential quote of the new year.
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#6 User is offline   gnasher 

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Posted 2010-July-13, 01:55

I'm not completely sure about this, but how about:

(A) xxx xxxx Axx xxx

(B) xxx xxxx Qxx Qxx

Opposite a 10-count, the ace is likely to be more useful, because it's a trick, an entry, a control, etc. Opposite a 20-count, the queens between them may be worth more than one trick or more than one entry, and control is unlikely to be an issue.

The companion 10- and 20-count might be
AQJxx xx xxx Kxx
AQJxx Qx KJx AKx or AQJxx Kx Kxx AKx
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
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#7 User is offline   gwnn 

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Posted 2010-July-13, 03:21

quiddity, on Jul 12 2010, 10:03 PM, said:

I guess a trivial example would be
A: 13-card solid suit
B: 20-point balanced hand

huh.
... and I can prove it with my usual, flawless logic.
      George Carlin
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