33 hcps and 13 top tricks. Assuming the opponents are silent, can you confidently bid this grand (7NT) with the system of your choice?
Test your system! Can you confidently bid it?
#1
Posted 2009-November-19, 05:57
33 hcps and 13 top tricks. Assuming the opponents are silent, can you confidently bid this grand (7NT) with the system of your choice?
#2
Posted 2009-November-19, 06:20
4C ( Minorwood ) for the uninspired.
You find the missing key card, ♣ A .
Next is specific K-ask, and you find the ♦ K.
Followup with 2nd K-ask, and you find the ♥ K.
Now can count: 5c, 5d, sA, hAK.
But before you bid 7NT, you recall partner has made a 2/1 2C call in the past
with only 4 cards.
Safer would be 7C but it will cost you at MP scoring except you will beat out all of the 6NT contracts.
#3
Posted 2009-November-19, 07:13
1♦ - 2♣ (nat may have longer ♣ ; nat F2NT)
2♥* - 2♠* (GF support or bal ; relay without 4M)
3♣ - 3♥ (GF support 4+♣ ; something in ♥, not in ♠)
4♣ - 4♦ (sets trump, start slam auction ; cue)
4NT - 5♣ (RKC ; 1/4)
5♥ - 5♠ (King ask ; ♠K or ♥K+♦K)
5NT - 7♣ (general grand slam try ; 5th ♣)
7NT?
Up until 5NT it's pretty straight forward with some luck that we can show the Kings at 5♠, but the 7♣ bid may be a bit biased. If you decide to bid 6♣, North will definitely bid on with 6NT (or maybe 6♦ still looking for grand).
#4
Posted 2009-November-19, 07:20
3NT-5♣
5♦-5♥
5♠-6♦
7NT
3♠ forces 3NT
5♣ is slam-forcing with a (332)5 shape. (4♣ would show diamonds, 4♦ both minors, 4♥/♠ five clubs and a second suit, 4NT a non-forcing (332)5 slam try. Higher bids show (332)5 but slam-forcing.)
The rest are cue-bids.
#5
Posted 2009-November-19, 07:46
3 NT 4♣ (no 4 or 5 card major) (quant. RCKB for clubs)
4 ♥ 4♠ (like clubs 4 KCs) (Queen?)
5 ♣ 5♦ (yes, no king) (something else to show?)
6♦ 6 ♥ (5. diamond) (anything else?)
7 Club/NT For a hand with 4 KCs and no kings, it is perfect with the nearly solid diamonds)
Roland
Sanity Check: Failure (Fluffy)
More system is not the answer...
#6
Posted 2009-November-19, 07:59
2C - 2D
2H - 3C
3D - 3N
4C - 4D
4H - 5C
7N - p
1C = 16+
1N = 8-14 balanced
2D = 12-14
3C = 5 clubs
3N = 2335
4D = 1 ace
5C = red kings or black kings
#7
Posted 2009-November-19, 08:10
2NT(22+ balanced, 2-3 spades)-3♣(puppet)
3♦(no major)-3♠(minor interest)
or
2♣(normal)-2♦(GF)
2NT-3♠(minor interest)
or
2NT-3♠(minor interest)
Then...
4♣(slam interest)-4♦(clubs)
4♥(RKCB clubs)-4NT(1) or 4♠(1) depending on style
5♦(kings?)-5♥(heart King)
5NT(diamond?)-7♣(yes)
And then Opener pops 7NT.
Interesting hand. Opener bypasses 3NT to bid 4♣ to show serious minor-suity interest, which forces Responder to bid one-up to show clubs, which allows Opener to use 4♥ as RKCB, which forces the King ask up one, which forces the use of 5NT to show or ask for the diamond King. You really need a good partnership grasp of surrogate bidding for this hand, IMO.
-P.J. Painter.
#8
Posted 2009-November-19, 09:43
#9
Posted 2009-November-19, 09:45
3C......3H (5+/4+, 17hcp+)(I had a nat. GF Club hand and cue)
3S......4D (cue)(cue)
4NT....5C (RKCB)(1 key)
5NT....6D (ask Kings)(Diam. King)
6H..... (Heart King?) (etc...)
Opner can now count 13/14 tricks (1S, 2H, 5D, 5/6C)
Not very scientfic but it works
#10
Posted 2009-November-19, 09:55
4C - 4D
4NT - 5C (1/4)
5H - 5S (no spade king)
5NT - 6D (heart king, no diamond queen)
7C
Opener doesn't know responder has 5 clubs, can't count 13 tricks in notrump but can count 13 tricks in clubs. Lose 2.
#11
Posted 2009-November-19, 10:20
hanp, on Nov 19 2009, 04:55 PM, said:
4C - 4D
4NT - 5C (1/4)
5H - 5S (no spade king)
5NT - 6D (heart king, no diamond queen)
7C
Opener doesn't know responder has 5 clubs, can't count 13 tricks in notrump but can count 13 tricks in clubs. Lose 2.
Can opener ask about ♥Q at this point? It would be a shame to go down in 7♣ opposite Qxx KQx Kxx Axxx, with 7NT making on a black-suit squeeze. Responder can't safely convert to 7NT, because for all he knows the diamonds might need ruffing good.
#12
Posted 2009-November-19, 11:05
#13
Posted 2009-November-19, 12:55
hanp, on Nov 19 2009, 10:55 AM, said:
4C - 4D
4NT - 5C (1/4)
5H - 5S (no spade king)
5NT - 6D (heart king, no diamond queen)
7C
Opener doesn't know responder has 5 clubs, can't count 13 tricks in notrump but can count 13 tricks in clubs. Lose 2.
Yes, the 2nd step, 5H, is specific K-ask ( 1st step, 5D, would be trump Q-ask ).
The standard replies ( for me ) to the 1st K-ask here are:
5S = ♠ K ( cheapest reply showing a K )
5NT = ♥ K ( NT always shows the feature in the asking suit ( ♥ here )
and denies ♠ K.
6C = no Major suit K
( No need to reply 6D since ♦ K shown by 4D cue , and you don't want to go above 6C with neither Major K ).
- - - - - - - - - - - - - -
Do you really want to make another "ask" ABOVE the 6C level ? It will commit you to at least 6NT with either your method ... or higher with mine.
[ In my method you can only make a 2nd KING-ask ... and not ask for an outside Q with the 2nd-ask. And anyway, if you did use 6S as an outside Q-ask, that looks like asking for the ♠ Q . Partner may think YOU have the ♠ K ] and put you in the grand with the ♠ Q... which he does have here ! !.
They only way to effectively get in a 2nd-ask when a minor suit is trump is with Minorwood or Redwood ( Kickback ) .
#14
Posted 2009-November-19, 12:58
#15
Posted 2009-November-19, 13:08
hanp, on Nov 19 2009, 01:58 PM, said:
aaahh, ty... I understand your replies now...Kantar's Spiral Scan.
[ I don't know enough about it, except it makes my head explode ] .
#16
Posted 2009-November-19, 13:29
Little Kid, on Nov 19 2009, 02:57 PM, said:
33 hcps and 13 top tricks. Assuming the opponents are silent, can you confidently bid this grand (7NT) with the system of your choice?
Trivial...
#17
Posted 2009-November-19, 20:27
Apollo81, on Nov 19 2009, 07:43 AM, said:
This hand is essentially what I'll find out from partner (minus the T) when I do a strong club relay. This hand is pretty much what the relay is for.
1♣-2♦ (16+ hcp; 8+ hcp, 2+ controls, 5+ clubs single suit)
2♥-2♠ (r; short spades or 7222)
2nt-3♦ (r; 2=3=3=5)
3♥-4♣ (r; 4 controls)
4♥-5♦ (r; exactly one each in ♣♦♥ and 0 or 2 in ♠)
At this point you know responder is xx Kxx Kxx Axxxx where x is any card up to and including a Q, which is good enough to bid 7nt.

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