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What's the min hand to do this:
(1♣)-x-(1♦)-p;
(2♣)-x-(p)-2♠;
(3♣)-3♠
?
What would 3♦ and 3♥ be instead of 3♠?
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How much for this sequence?
#2
- Andy Bowles
-
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Posted 2009-September-02, 03:18
3D/H shows a very strong flexible hand, probably with only five of the suit. 3(54)1 would be ideal, but we're not always dealt that.
... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
#3
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Posted 2009-September-02, 03:36
Stephen Tu, on Sep 2 2009, 03:11 AM, said:
What's the min hand to do this:
(1♣)-x-(1♦)-p;
(2♣)-x-(p)-2♠;
(3♣)-3♠
?
What would 3♦ and 3♥ be instead of 3♠?
(1♣)-x-(1♦)-p;
(2♣)-x-(p)-2♠;
(3♣)-3♠
?
What would 3♦ and 3♥ be instead of 3♠?
Around AQJx AKJx KQJx x will do, agree with Andy that 3(54)1 for 3♦/3♥ shapes are typical
Ming
--Always remember you're unique. Just like everyone else.
--Always remember you're unique. Just like everyone else.
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