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three dee

#1 User is offline   gwnn 

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Posted 2009-August-30, 04:24

1S-1NT
2C-2S
3D???

Can you give a hand that would bid like this? 1NT was forcing and 2C promised 3.
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#2 User is offline   effervesce 

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Posted 2009-August-30, 04:32

AQJxx x Axx AQxx or so, 5134/5044/6034 type shape.
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#3 User is offline   Fluffy 

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Posted 2009-August-30, 08:04

IMO this sequence denies a 6th spade, with the only possible fit on a minor it must be 5044 or 5035 with extras (almost worth a jump the previous round)
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#4 User is offline   Jlall 

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Posted 2009-August-30, 08:23

effervesce, on Aug 30 2009, 05:32 AM, said:

AQJxx x Axx AQxx

This is a good example hand, and I agree with fluffy that 5035 is possible while 6034 is not (since 3D is NF).
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#5 User is offline   pooltuna 

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Posted 2009-August-30, 08:53

gwnn, on Aug 30 2009, 05:24 AM, said:

1S-1NT
2C-2S
3D???

Can you give a hand that would bid like this? 1NT was forcing and 2C promised 3.

I can't! But I am sure some of the ones who play 2♣ is "forcing" in this auction will come up with a hand.
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#6 User is offline   Lobowolf 

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Posted 2009-August-30, 09:39

pooltuna, on Aug 30 2009, 09:53 AM, said:

gwnn, on Aug 30 2009, 05:24 AM, said:

1S-1NT
2C-2S
3D???

Can you give a hand that would bid like this? 1NT was forcing and 2C promised 3.

I can't! But I am sure some of the ones who play 2♣ is "forcing" in this auction will come up with a hand.

So will the ones who play it non-forcing...

Since 2♣ isn't non-forcing, it's less than the 19 or so points that would be required for a jump-shift. Since 2♠ was weak, it's a hand that could conceivably make game opposite a low-ranging 1NT(F) response (i.e. up to 9 or so - so not a minimum opener). Then fill in the blanks with the distribution suggested by the sequence. The 5=1=3=4 17-count suggested by effervesce seems ideal and typical.
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#7 User is offline   aguahombre 

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Posted 2009-August-30, 09:52

Does anyone agree with me that 2NT should articially show the 5134 17 count to allow a club partial if responder has, say, 2 4 3 4 and a weak response? I know the 5224 17 count would then be lost or have to make the same 2NT bid, but is that bad?
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#8 User is offline   Fluffy 

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Posted 2009-August-30, 10:11

2NT shows for me the 15-17 balanced hand. You have to open all 5 card major balanced hands in 1NT for that to be even playable.
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#9 User is offline   aguahombre 

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Posted 2009-August-30, 10:28

Fluffy, on Aug 30 2009, 11:11 AM, said:

2NT shows for me the 15-17 balanced hand. You have to open all 5 card major balanced hands in 1NT for that to be even playable.

yep
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#10 User is offline   FrancesHinden 

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Posted 2009-August-30, 11:18

aguahombre, on Aug 30 2009, 04:52 PM, said:

Does anyone agree with me that 2NT should articially show the 5134 17 count to allow a club partial if responder has, say, 2 4 3 4 and a weak response? I know the 5224 17 count would then be lost or have to make the same 2NT bid, but is that bad?

If partner really had a very weak 2434 wouldn't he pass 2C?
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#11 User is offline   aguahombre 

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Posted 2009-August-30, 15:47

FrancesHinden, on Aug 30 2009, 12:18 PM, said:

aguahombre, on Aug 30 2009, 04:52 PM, said:

Does anyone agree with me that 2NT should articially show the 5134 17 count to allow a club partial if responder has, say, 2 4 3 4 and a weak response? I know the 5224 17 count would then be lost or have to make the same 2NT bid, but is that bad?

If partner really had a very weak 2434 wouldn't he pass 2C?

no i dont think it would be a great idea to eschew the 5-2 fit and leave the reds open for the opps at the two level in order to play a possible 4-3 fit. But, still would like opinions about the possibility of using 2nt rather than 3D on the given 5-1-3-4 17 count...
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