Posted 2008-December-22, 16:35
I find the misguess at trick one to be highly unlikely, but that is what you are specifying.
Given that trump are 3-1, you have two choices - the 50-50 shot at the ruffing heart finesse or play the player with 3 trump to have 4 or more clubs. Given that RHO won the ♦A and shifted, one might assume that the ♦A was singleton. But, then again, he saw you rise with the ♦K at trick one - hardly a normal play for a declarer to make if he had 2 or 3 small in hand. Perhaps RHO thinks that you have the ♦Q and you are trying to induce a second round of diamonds. So, it is not entirely clear that RHO has a singleton diamond.
If you assume that RHO had a singleton diamond Ace and it turns out that RHO is long in spades, it would not be unreasonable to assume that RHO had longer hearts than LHO and was favored to hold the HK. If RHO is "known" to have only 1 diamond along with his 3 spades, he has 9 unknown cards to LHO's 8 unknown cards. That makes RHO a slight favorite to hold the ♥K. Since the ♥K rates to be with RHO, you can only succeed if RHO has at least 4 clubs. So, you ruff a heart, lead a club to hand, ruff a second heart and cash the Q and J of clubs from dummy, pitching diamonds. If RHO ruffs in you are dead. But if the clubs live, you are home.
The same analysis would lead to the conclusion that RHO is a slight favorite to hold 4 or more clubs, whether he has the ♥K or not.
The percentage line, all other things being equal, would be to pull trump, unblock the club honor and take a ruffing heart finesse through LHO. If this wins, you claim, ruffing your last heart in dummy and throwing your diamonds on the high clubs. But all other things are not equal.
The question is, is it reasonable to assume that the ♦A is singleton?
opps silent.
... - P
2♣ - 2♦
2NT - 3♣*
3♠ - 4♥
5♣ - 6♠
all pass
* -- puppet, 3♠ showed 5.