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doblo actually, two doblos

#1 User is offline   gwnn 

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Posted 2008-October-19, 16:02

1♣-p-1♦-X
2♣-2♥-X

and

1♣-p-1♦-X
2♣-2♥-p-p
X

What are these doubles? Can you specify an example hand or two?
... and I can prove it with my usual, flawless logic.
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#2 User is offline   gnasher 

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Posted 2008-October-19, 16:12

The first one is for penalties. There is no point in playing non-penalty doubles opposite a well-defined one-suiter. Axx KQJ9 Axxxx x would be nice.

The second one, if it exists at all, shows a hand that wants to bid 3♣, but is giving partner the option of defending. Perhaps KQx Kxx x AJ10xxx.

This post has been edited by gnasher: 2008-October-19, 16:14

... that would still not be conclusive proof, before someone wants to explain that to me as well as if I was a 5 year-old. - gwnn
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