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bam hand

#1 User is offline   gwnn 

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Posted 2008-September-23, 13:33

p-p-1♦-X
1♥-2♠-p-p
3♥-p-p-p

Partner likes to make light takeout doubles, RHO isn't the best bidder in the world.

Scoring: BAM


♠K-9-7-A partner showed an even number of spades.
♦2-9-T-K
♠3-5-T-8

Your turn. Sorry there's no other signal except the spade count.
... and I can prove it with my usual, flawless logic.
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#2 User is offline   andrei 

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Posted 2008-September-23, 14:56

♣
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Before internet age you had a suspicion there are lots of "not-so-smart" people on the planet. Now you even know their names.
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#3 User is offline   Codo 

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Posted 2008-September-24, 00:24

♦

IF pd has 1 diamond (he doubled for take out) this is not bad. Chance: 0%
If he has two, it is bad. But in that case, declarer has 4 diamonds and may had bidden diamonds instead of rebidding his hearts.
If pd has three, we maybe get a ruff (pd rates to have some Heart Honours) and we surely cut declarer of from the diamonds.
Same can be true if partner has 4 diamonds.

If I play a club, declarer surely won't take the king after this bidding and the play so far, so no sense in that. As he should have 6 or more trumps, there is no sense to lead a trump. And as he should have 2 spades, there is no sense in playing spades either.
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#4 User is offline   Gerben42 

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Posted 2008-September-24, 00:43

I love count signals. They usually mean that you know declarer's distribution, but that you have a complete guess about the game plan.

Anyway, given that partner has 4♠ and 3♥, this means that declarer has only 5. To bid like this he must be 2=5=4=2, I guess, leaving partner with 4=3=2=4.

My plan is to cash the ♠Q (leaving the possibility that partner has the Jack) and return a ♣, making declarer guess.
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#5 User is offline   Tomi2 

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Posted 2008-September-24, 03:27

Gerben42, on Sep 24 2008, 01:43 AM, said:

I love count signals. They usually mean that you know declarer's distribution, but that you have a complete guess about the game plan.

Anyway, given that partner has 4♠ and 3♥, this means that declarer has only 5. To bid like this he must be 2=5=4=2, I guess, leaving partner with 4=3=2=4.

My plan is to cash the ♠Q (leaving the possibility that partner has the Jack) and return a ♣, making declarer guess.

they you should watch this more carefully. partner returned ♠3 and not ♠2, so he is not interested in clubs IMO, but he sees the chance of the ♦ruff, I play him for the 4333 distr. "I have fit in all suits" and ace of hearts
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#6 User is offline   gwnn 

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Posted 2008-September-24, 04:03

Sorry the ♠3 doesn't mean anything. ♠7 showed an even number. No other signals. I'm not saying that absence of signals is good, but this is how it is.
... and I can prove it with my usual, flawless logic.
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#7 User is offline   gwnn 

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Posted 2008-September-25, 15:56

a diamond keeps it to 9 tricks, the rest lets through 10 tricks. I played a club which seemed obvious at the time. Other table:
1♦-p-1♥-1♠
x-2♠-3♥-end
Identical first three tricks but now west played a diamond without a thought. 1 board to them.

... and I can prove it with my usual, flawless logic.
      George Carlin
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#8 User is offline   pclayton 

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Posted 2008-September-26, 10:27

Just read this, and agree with a diamond. Partner has a sure trump entry and has to have 3 diamonds. If declarer has four diamonds, then we aren't getting a 2nd club trick anyway.
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