How to bid this Can you bid these hands to 7
#1
Posted 2008-August-20, 19:57
opposite
KQ542,97,AT5,AT7
Matchpoints. This was table auction
2NT - 3H
3S - 5NT ( Pick a slam)
6S
It would be interested to see Strong Club Auctions too.
#2
Posted 2008-August-20, 21:02
I would play 5N as a quantitative invitational to grand with 5 spades, not that it ever comes up.
#3
Posted 2008-August-20, 21:05
Transfer to spades, then use key-card gerber, and confirm all of the keycards without asking about the Q of spades. Partner (he of the 2N opener) now knows all of the key components of your hand, and can bid the grand himself if desired.
#4
Posted 2008-August-20, 21:13
dcvetkov, on Aug 20 2008, 08:57 PM, said:
opposite
KQ542,97,AT5,AT7
Matchpoints. This was table auction
2NT - 3H
3S - 5NT ( Pick a slam)
6S
It would be interested to see Strong Club Auctions too.
2nt=6nt MP KISS
#5
Posted 2008-August-20, 21:37
KQ542,97,AT5,AT7
You want a big C auction?
1C 1H 9+ with S
1S 2S short H
2N 3D exactly 5233 shape
3H 4D 5 AK controls
4H 5D controls in S, D, C not H
5H 5N Q of S
?
? = pick your slam. All of opener's bids are relays. You actually have room to find the J of S if resp happens to have it, but I was too lazy to post this.
#6
Posted 2008-August-20, 21:57
dcvetkov, on Aug 20 2008, 08:57 PM, said:
opposite
KQ542,97,AT5,AT7
Matchpoints. This was table auction
2NT - 3H
3S - 5NT ( Pick a slam)
6S
It would be interested to see Strong Club Auctions too.
Another big club auction with transfer positives:
1♣-1♥(A)
1♠(
2♠(D)-3♦(E)
6NT/7NT (F)
A: 8+HCP and 5 spades
B: Confirms spades as trump (3+) and asks for controls
C: 5 controls (A=2; K=1) Since opener has 6 controls, he knows that only a king is missing.
D: Trump ask
E: 5-card suit with 2 of the top 3 honors
F: Opener can count 12 top tricks in NT and either settle for that, or hope the spades will split or partner will have the jack.
Call me Desdinova...Eternal Light
C. It's the nexus of the crisis and the origin of storms.
IV: ace 333: pot should be game, idk
e: "Maybe God remembered how cute you were as a carrot."
#7
Posted 2008-August-20, 22:06
-P.J. Painter.
#8
Posted 2008-August-21, 09:13
opposite
KQ542,97,AT5,AT7
In my big club method:
1♣ - 1♥ (Spades, GF)
1♠ (suit ask) - 2♦ (Exactly 5♠, 2 of top 3)
2♥ - (relay ask in ♣) - 3♦ (Ace or Void)
3♠ - clarifying - 4♣ - Ace
4♦ (ask in ♦ - 5♣ Ace or Void
5♥ - clatifiying - 5NT Ace
6♣ - heart ask - 6♥ - 3rd round control (Qxx(x) or xx)
? whatever
Not sure if I really want to risk grand here, since you need 3-2 spades to make, with the ability to count 12 tricks on any spade split.
Also, can have a much more compact auction if opener assumes the controls are aces...then the actuion continues
3♥ (♦ ask) - 4♦ (Ace or V)
4♥ (♥ ask) - 5♦ (Ace or V)
?
#9
Posted 2008-August-21, 09:58
2N - 3♥
3♠ - 5x
not as EKCB but answering as though Opener key carded with 4N. I don't know if they can diagnose a 5-3 fit and then answer, but the solution to me seems to be that opener needs to be doing the asking here.
I thought Kleinman's Yellow Rose would be able to handle this hand but it doesn't appear as though it can.
Edit: I just ran this by Walter Johnson and he said Meckwell would bid
2N - 3♥
3♠ - 5♣
5♦ - 5♠
7N
(perhaps he meant 5N instead of 5♠ - I didn't press him).
#10
Posted 2008-August-21, 10:15
pclayton, on Aug 21 2008, 10:58 AM, said:
2N - 3♥
3♠ - 5♣
5♦ - 5♠
7N
(perhaps he meant 5N instead of 5♠ - I didn't press him).
I'm pretty sure they use the cheapest bid to deny the queen, which I also think is best. Clearly given that, south has nothing extra to show other than the queen, so I'm pretty sure they would bid 5♠.
#11
Posted 2008-August-21, 11:10
2NT - 3♥
4♣ - 4♦
4NT - 5♣
5♦ - 5NT
7NT
2NT=20-21, 3♥=GF trf, 4m=cue
Harald
#12
Posted 2008-August-21, 11:16
#13
Posted 2008-August-21, 12:42
matmat, on Aug 21 2008, 12:16 PM, said:
Yes. Opener's LHO has that, but the poor chap also has KQJ10x in hearts.
-P.J. Painter.
#14
Posted 2008-August-21, 12:47
matmat, on Aug 21 2008, 11:16 AM, said:
It is a myth that you need grand to be 75% or s.th. like that to be worth bidding. If you can be sure your opponents will be in a slam (for example, responder has a nice 13 count opposite a 2N opener), then 56% is enough.
#15
Posted 2008-August-21, 12:55
cherdano, on Aug 21 2008, 10:47 AM, said:
matmat, on Aug 21 2008, 11:16 AM, said:
It is a myth that you need grand to be 75% or s.th. like that to be worth bidding. If you can be sure your opponents will be in a slam (for example, responder has a nice 13 count opposite a 2N opener), then 56% is enough.
Except for it's matchpoints. You'd want an estimate of how many will be in 6♠, 6NT, 7♠, 7NT, something else.
#16
Posted 2008-August-21, 13:08
cherdano, on Aug 21 2008, 10:47 AM, said:
matmat, on Aug 21 2008, 11:16 AM, said:
It is a myth that you need grand to be 75% or s.th. like that to be worth bidding. If you can be sure your opponents will be in a slam (for example, responder has a nice 13 count opposite a 2N opener), then 56% is enough.
Arend, where are you getting 56% from?
#18
Posted 2008-August-21, 13:20
karlson, on Aug 21 2008, 02:15 PM, said:
NV. Lose 14, Win 11. 14/25 = 56%
Apparently you need that heart nine to bid the grand when vulnerable, to get that necessary extra 0.6667% edge.
Shoot! That only gives you an extra 0.39% chance! Maybe the 10 would have been enough. Or, a stiff honor. Maybe it is better...
-P.J. Painter.
#19
Posted 2008-August-21, 13:38
1♠* - 2♠*; relay - single suited with short hearts or 7222
2nt* - 3♦*; relay - 5233
3♥* - 4♦*; relay - 5 controls
4♥* - 5♦*; relay - 1 of top 2 ♠, 1 of top 2 ♦, 1 of top 2 ♣, 0 or 2 top 2 ♥
5♥* - 5NT*; relay - Q♠ but no Q♦
7nt (if ♠ split 3-2 or responder has the J♠ this makes)
over 3♦ could also continue
3♠* - 4♣*; key card spades - 3 or 0 key cards
4♥* - 5♠*; Q ask? - Q♠ but no K's
7nt
#20
Posted 2008-August-21, 13:51
Echognome, on Aug 21 2008, 12:55 PM, said:
cherdano, on Aug 21 2008, 10:47 AM, said:
matmat, on Aug 21 2008, 11:16 AM, said:
It is a myth that you need grand to be 75% or s.th. like that to be worth bidding. If you can be sure your opponents will be in a slam (for example, responder has a nice 13 count opposite a 2N opener), then 56% is enough.
Except for it's matchpoints. You'd want an estimate of how many will be in 6♠, 6NT, 7♠, 7NT, something else.
Oh, matchpoints! Given that the decision is only between 6N and and 7N, you actually need a chance of
50% + 1/2 the percentage of those in 6S or lower - 1/2 the percentage of those in 7S
E.g. if 30% are in 6S and 10% in 7S, you would need a 60% chance of making for 7N to be worthwhile.
[Hmm, I guess I am ignoring the cases where you go down 2 in 7S but only 1 in 7N.]

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