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Suit combo

#21 User is offline   dburn 

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Posted 2008-July-15, 18:53

Echognome, on Jul 15 2008, 07:04 PM, said:

I'm just wondering, isn't it equivalent after we've seen 3 cards played from opponents that the odds are just 12 to 11 based on vacant spaces?  Isn't that much easier than all of the combinatorics above?

Very much so. The exercise in futility above was an attempt to show how distributional probabilities are calculated in terms of vacant places. Or to put it another way, I was bored, and I didn't see why I should be the only one.
When Senators have had their sport
And sealed the Law by vote,
It little matters what they thought -
We hang for what they wrote.
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