What agreement do you have (or would want to have) about following REDBL and DBL:
1)
2NT-3C
3D-3S-(DBL)
REDBL
3C: Niemeyer
3D: 1 or 2 4 card Majors (no 5 card)
3S: 4 card H
RHO now DBL's for lead.
How do you play REDBL in this situation?
- Fit H and 1st control in S?
- Or 4 card S and proposal to play 3S REDBL?
2)
(1H)-2C-(2D)-DBL
2C= 4 card S and 5+Clubs, 10-15 pts
How do you play DBL?
- penalty (probably having both D and H)
- info and what is typical hand then?
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DBL en REDBL
#2
Posted 2008-April-09, 11:08
You can use Klinger's idea:
Pass = no stop in spades. Pard rdbls to ask for system ON.
Rdbl = I got spades.
Other = normal response with spade stop.
This applies to all artificial bids after 1NT, including transfers.
Pass = no stop in spades. Pard rdbls to ask for system ON.
Rdbl = I got spades.
Other = normal response with spade stop.
This applies to all artificial bids after 1NT, including transfers.
#3
Posted 2008-April-09, 11:44
1) Suggesting playing in 3Sxx
2) I have never played this method, but if I did I would expect double of 2D to be penalties, on the basis that overcaller has already narrowly defined his hand so there is no need to play double as take-out.
2) I have never played this method, but if I did I would expect double of 2D to be penalties, on the basis that overcaller has already narrowly defined his hand so there is no need to play double as take-out.
#4
Posted 2008-April-09, 14:28
What she said.
The easiest way to count losers is to line up the people who talk about loser count, and count them. -Kieran Dyke
#5
Posted 2008-April-10, 02:55
1) Suggesting 3♠xx in a 4-3 fit.
2) Negative. Double of opponent's forcing bid cannot be penalty!!!
2) Negative. Double of opponent's forcing bid cannot be penalty!!!
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