Halo, on Nov 29 2007, 02:39 PM, said:
dburn, on Nov 29 2007, 02:12 PM, said:
Halo, on Nov 29 2007, 01:45 PM, said:
Am I misreading or do you need to take away West's spade six as well for 4135 in North to beat declarer?
I should imagine you are misreading, since West does not have the spade six.
Thanks
The six hearts - just good enough to win against 4135?
I am not sure what I am being asked here. To reduce the problem to simple terms, we fix the East-West hands as:
North has doubled 1
♥ for takeout, then raised South's 1
♠ response to 2
♠. West declares 3
♥ on the lead of a trump.
We assume that North has the ace and queen of spades, the ace of diamonds, and a singleton trump in a 4=1=5=3, 4=1=4=4 or 4=1=3=5 shape. We also assume that South has two clubs higher than North's second lowest club.
Given these conditions, West can make 3
♥ against any defense, provided that West can guess North's distribution. No line of play, however, caters for every one of the three distributions given above.
In all cases, West can succeed by winning the first heart with dummy's queen. This is the only line that succeeds against 4=1=4=4 under the conditions given. Now:
Against 4=1=5=3, which we will call distribution 1, West has two possible winning lines.
[1A] She can cash two clubs and ruff the third, then play a spade to the king and North's ace. North attempts to exit with
♠Q (any other play is obviously fatal), but West discards her remaining club. Now North must concede a ninth trick either to West's
♦K or East's
♠J (dummy does not need
♠10 in this variation).
[1B] She can play a spade to the king at trick two. North plays a club, overtaken by South, but declarer cashes
♣AK, ruffs a club, and passes
♠J to North who must concede a ninth trick on her return (dummy does need
♠10 in this variation).
One of jdonn's suggested lines, that of winning
♥Q and running hearts with the aid of a second-round finesse to squeeze North, fails if distribution 1 exists (call this line 1J). Another, that of winning the first trick with
♥10 and playing a spade, succeeds provided that he transposes into [1B] above and does not attempt to squeeze North by running hearts.
Against 4=1=4=4, which we will call distribution 2, West has essentially only one winning line:
[2A] She must play a spade to the king and North's ace, then win a club exit, cash a second club, and ruff a third. Then, she ruffs a spade and exits with a club to North. North exits with
♠Q, ruffed by declarer, who exits with a diamond and waits to make three more trump tricks.
Neither of jdonn's suggested lines above succeeds against distribution 2. If, however, South has only one club higher than North's second lowest club, jdonn can succeed by winning the first heart with the ten and playing a spade, then ducking North's attempted club exit unless South overtakes it. Later, the run of the trumps will strip-squeeze North into conceding a trick to
♦K one way or another.
Against 4=1=3=5, which we will call distribution 3, West can succeed after winning
♥Q only by
[3A] at once drawing trumps with the aid of a finesse. This is line [1J] above. After winning trick 1 with
♥10, declarer can succeed by playing a spade at once, or after crossing to
♥Q and following line [1J].
In essence, with no significant spot cards declarer must choose at an early stage which line to follow. If the club spots are such that declarer considers it more likely than not that South cannot overtake both of North's two lowest clubs, then line [1J] is perhaps preferable to line [2A], but it is very close.
Finally, to answer Halo's actual question, the six of hearts is of no relevance whatsoever.