Posted 2007-July-22, 07:23
1NT is 11-13/14-16V
1♣ if balanced is 17+
1♦, 1♥, and 1♠ all show 4 or longer in suit opened
So what does a 5-3-3-2 with 5♣s open if outside the 1NT range and less than 17? This is not covered on page 51, the NT Ladder, nor on page 40 for the 1♦ opener (which starts off as describing the bid as 10-15 HCP & 4+♦), but the overview on page 5 says, for 1♦:
"4+♦ CANAPE IF 5+-4 DISTRIBUTION; MAYBE 3♦ (NT), RARELY 2♦ (3325)."
So it appears that the 1♦ bid is:
a ) 10-15 HCP & 4+♦; OR
b ) balanced without a four card major, less than 17, outside the range of 1NT
Since b with 2-3♦s is not rare, I suggest not indicating that 1♦ is 4+♦s
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Question: say one opens 1♠ NV with 14-16 balanced and 4♠s. Responder bids 1NT with no ♠ fit and less than a GF (which would bid 2♣) and not a hand that would respond 2♦ or 2♥ (five card or longer suit, about 10 points). What does opener do next with 14-16 balanced over the 1NT response?
Additional question: if NV 1♦, 1♥, and 1♠ handles 14-16 balanced, should not the notes (especially the overview) describe these bids as 10-16 or 10-15(16)?
Bonus question: 1♦-3♦ is LR 5+♦s without a 3M. Does LR with a 3M respond 1NT or was the intent to respond 1M, so 1♦-1M, which "TEND TO BE 5-CARDS" can be 3 sometimes?
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As you fix disclosure problems as noted above, it will be easier to spot system gaps. For example in the notes 1♠-2♥ is “about 10 pts and 5+♥” – so is the range here 10-11, 9-11, 8-11, good 8 to poor 12, good 9 to poor 12, good 8 to poor 11 etc.? If opener NV has 14-16 balanced and it goes 1♠-2♥, if just 2♥s do they jump to 3NT, or just jump to 3NT if 15-16, and bid 2NT “to play” if 14? Knowing the range for 2♥ helps work these out.
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