FrancesHinden, on Jul 23 2007, 07:16 AM, said:
...this doesn't really belong ni the BI forum, but there are still some vague possibilities for making the contract if you play a diamond to the 9 and East discards....
♣♦♥♠
There seems to be at least one other layout (other than those identified by Frances already) that will help us. {NB West must have been dealt 2 clubs exactly, else would not he surely lead one now and make declarer ruff with South's last trump?}
That is, if West bid 1 spade with:
♠87643
♥xx
♦AJ64
♣43
and East was dealt QJ of spades tight.
Then, we can win the diamond 9 at trick five, East discarding, and take 4 spade tricks (tricks 6 thru 9) from the top. Throw away 2 hearts and one club from North on tricks 7,8 and 9.
Trick 10, we ruff South's last spade in North.
Trick 11, return to South with North’s last heart.
Lead a heart from South, and West is finessed. He has J6 in trumps and North has Q8 behind him.
Is this (East holding QJ of spades tight) more likely that East being dealt JT of diamonds tight? I think it’s
less likely because EW were dealt 7 spades and only 5 diamonds. So I think the percentage play is the Queen, but it's a lot more fun if the 9 is right b/c of the layout above.
NB -- Maybe the above reasoning on which is more probable (JT of
♦ vs. QJ of
♠) is incorrect, because we know West has 4+ spades. So the 7 EW spades cannot be divided arbitrarily (as the diamonds can be); West must have 4 or more of them. I think we can rule out his having 7 of them because surely he would have been bidding more.
So West has either 4,5 or 6 spades. Maybe that changes the probabilities sufficiently. Certainly, East is more likely to bid 3
♣ holding QJ of spades after his partner has bid spades. And I think West is more likely to rush in with a 4 club bid holding AJxx of diamonds, because it surely sounds like partner has a stiff diamond.