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Against NT, lead from a broken suit with length if their best holding in the suit is to your right.
What do you lead? Another bread and butter problem
#21
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Posted 2005-December-14, 14:35
The Grand Design, reflected in the face of Chaos...it's a fluke!
#22
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Posted 2005-December-14, 14:40
Much depends on their methods. If 1♠ would be bid on 4=3=4=2 or 4=2=4=3, then the 1N may be on 3=4=3=3 or 3=5=2=3. And declarer may have zilch in ♣.
If 1♠ promised shape, then 1N is far more likely to contain a more significant ♣ holding.
In the former case, I have not heard enough to lead anything but a ♣.
In the latter case, there is a strong(er) case for a non-♣ lead. If I were going to lead a non-club, I'd choose the ♠A, hoping that dummy does not hold the KJxx.
If 1♠ promised shape, then 1N is far more likely to contain a more significant ♣ holding.
In the former case, I have not heard enough to lead anything but a ♣.
In the latter case, there is a strong(er) case for a non-♣ lead. If I were going to lead a non-club, I'd choose the ♠A, hoping that dummy does not hold the KJxx.
'one of the great markers of the advance of human kindness is the howls you will hear from the Men of God' Johann Hari
#23
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Posted 2005-December-14, 17:25
1♠ does not promise shape. Oppos are bidding their suit up the line.
OTOH, my guess was that oppos do not have a lot of fit.
IMHO, it would be best to lead through LHO strength.
And ♠A allows you to have a look at dummy.
It may be just a lucky guess. IMO, the lead against a sequence 1x-1y-1z is a bit different than what you might choose after 1x-1N (not to mention 1N-all P).
Clubs are not a very attractive suit, and might as well be the main strength of E.
OTOH, my guess was that oppos do not have a lot of fit.
IMHO, it would be best to lead through LHO strength.
And ♠A allows you to have a look at dummy.
It may be just a lucky guess. IMO, the lead against a sequence 1x-1y-1z is a bit different than what you might choose after 1x-1N (not to mention 1N-all P).
Clubs are not a very attractive suit, and might as well be the main strength of E.
(1D)-P-(1H)-P-(1S)-
(1N)-all P