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Qxx is not the same as Axx
Qxx = needs 2 fineses to work, so it's closer to 3 losers than 2 losers. I'd evaluate it as 2.75 losers, or 3- losers.
Make it QTx and it's about 2 losers.
Axx = 2 losers
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likewise AKx xxx is far more powerful than Axx Kxx
Kxx = needs one finesse to work so about 2.5 losers
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and so on but LTC is the same which is where judgement comes into it!
This is because the RAW LTC is oversimplified.
In order to account losers properly, we need to account for the number of finesses that will be needed.
In many italian books by Chiaradia, Belladonna, Garozzo, etc, the first page is a table of honors combinations and how many losers are associated to it for the loser's count.
Accounting an equal number of losers for Axx = Kxx or for Qxx = Kxx, or Qxx = QJT is easy, but silly.
You need to account for fracional losers or some other ways that discriminates properly these holdings, where simple commonsense suggests they are far different.
"Bridge is like dance: technique's important but what really matters is not to step on partner's feet !"