When playing 1♦-1♥ = 4+♥, 6+H or GF all distribution, how does responder invite after 1♦-1♥-1NT since 2♣ is GF relay ?
I think of using 2♦ might be the solution to show 10-11H and asking for 3 cards ♥ and strength:
2♥ = 3♥, minimum
2NT = 2♥, minimum
3♣/♦=3♥+5♣/♦, maximum
3♥ = 3♥, maximum
3NT = 2♥, maximum
Therefore, we loose the natural 2♦ fit which can thus be found via 2NT over 1NT as puppet for 3♣ with either weak long ♣ or weak shapely ♦ fit.
Any comments ?

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