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PCB Hand #8

#1 User is offline   straube 

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Posted 2017-October-19, 21:18

AQT8 J8 K862 K93
Void AKQ732 QJT AQJT

South is captain. Let's say North shows pattern and 8 QPs at 4C. A good one for reverse relays no doubt.

1) With rules of short to long (and stop with odd for singleton or doubleton), king parity last

4D-4N even heart, odd club, even spade (KQT8 J8 A62x K93 still possible)
5C-5S odd diamond, DK
Cards placed

2) With rules of short to long (and stop with odd for singleton or doubleton), king parity first

4D-5C even kings, even heart, odd club
5D-5H even spade (KQT8 J8 Axxx K93 still possible)
5S-6C odd diamond (KQT8 J8 Axxx K93 still possible)


3) With rules of long to short (and stop for singleton only), K parity last

4D-4H even spade
4S-5N odd diamond, odd club, even heart (rule change), DK
Cards placed

4) With rules of long to short (and stop for singleton only), K parity first

4D-4S even K, even spade
4N-5S odd diamond, odd club, even heart (rule change) (KQT8 J8 A862 K93 still possible)
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#2 User is offline   foobar 

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Posted 2017-October-19, 23:53

View Poststraube, on 2017-October-19, 21:18, said:

AQT8 J8 K862 K93
Void AKQ732 QJT AQJT


4D....4H (relay; even K parity...could be S(AKQ)...K(D|C) among others)
4S....4N (relay; nothing in hearts; even spade...S(AKQ) is out the window. S(KQ)...D(A)...C(K) or the above?

Can relay, but won't be resolved:

5C....5S (relay; odds in +[)
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#3 User is offline   awm 

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Posted 2017-October-20, 07:02

Several things about this hand: 1. We would reverse relay 2. If we can't reverse relay, we would use a shortness-showing sequence.

Ignoring all of that:

4 - 4 (even spades)
4 - 5 (odd diamonds, odd clubs, even hearts).

At this point it's either:

AQ + K + K
KQ + A + K

But it does not really matter. Partner's heart jack is not something we can find out for sure, so I'd just blast six in either case. I suppose we can resolve via:

5 - 5NT (on the actual hand, we pair + since one has king and other other queen, and we show that lower suit has the king; on the other option we would pair + since one has KQ and the other neither honor, and bid 5 since higher suit has king).
Adam W. Meyerson
a.k.a. Appeal Without Merit
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#4 User is offline   yunling 

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Posted 2017-October-20, 21:30

4-4(ask 1&2, 0/3/6)
the ask is not effective with shortage in suit 1, but a next move is okay here since if partner is 1/4 in suit 2&3 5H signoff is still possible.

4NT-5NT(ask 2&3, 2/5 no honor in H even Kings)
KQ A K is still possible but won't matter
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#5 User is offline   sieong 

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Posted 2017-October-22, 00:47

EPCB.
4 - 4 (even )
4 - 5 (even odd odd )

At this point this converges to classic PCB, but one step worse.
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#6 User is offline   nullve 

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Posted 2017-November-01, 11:55

View Poststraube, on 2017-October-19, 21:18, said:

AQT8 J8 K862 K93
Void AKQ732 QJT AQJT

Auction, with some ambiguity left out:

(...)
4-4 (11-13 hcp (say); relay)
4-4 (even # of kings; relay)
5-5 (odd # of queens, no K; relay)
6-? (K, K, Q, no J).

So Teller could still have Qxxx xxx AKxx Kxx. :(

This post has been edited by nullve: 2017-November-02, 08:07

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